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greenskyy
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Homework Statement
A 10 cm * 10 cm * 10 cm box contains .01 mol of nitrogen at 20 degrees C.
What is the rate of collisions (collisions/s) on one wall of the box?
Homework Equations
[tex]\frac{N_{coll}}{t}=\frac{NAv_{x}}{2V}[/tex]
[tex]v_{rms}=\sqrt{\frac{3k_{B}T}{m}}[/tex]
The Attempt at a Solution
I'm really banging my head on the desk with this one. So far, I've calculated the following information.
T = 20 degrees C = 293 degrees K
N = .01 mol * avogadros constant = [tex]6.02*10^{21}[/tex] particles.
Nitrogen is diatomic, so the molecular mass is 28u.
m = molecular mass / avogadros constant = [tex]4.65*10^{-26} kg[/tex]
[tex]v_{rms}=\sqrt{\frac{3k_{B}T}{m}} = 511 m/s[/tex]
Plugging this into the first equation given
[tex]\frac{N_{coll}}{t}=\frac{NAv_{x}}{2V}[/tex] = [tex]\frac{Nv_{x}}{2*.1} = 1.54*10^{25}[/tex]
This answer is incorrect according to masteringphysics, and I have no ideas from here. If anyone could offer some suggestions I would be very grateful.