Thevenin Circuit: Help Me Verify My Solution

In summary, the student attempted to find an equivalent circuit for a Thevenin's circuit but was unable to do so due to a conceptual misunderstanding. After correcting the mistake, the student was able to find the Vth and Rth values for the circuit and was able to solve for the equivalent Norton circuit.
  • #1
vikasagartha
15
0

Homework Statement


Ive never done Thevenin equivalents before, and I am not sure if I have removed the correct "load component". Could someone please take a look @ my solution and let me know if I have done this correctly? Thanks in advance! I really appreciate it!
Circuit Diagram:
https://www.dropbox.com/s/q5kubgapyu89blt/Screenshot from 2014-09-06 10:15:12.png?dl=0


Homework Equations


V=IR, KCL

The Attempt at a Solution


Written by hand, screenshot attached.
https://www.dropbox.com/s/3u4ku96uvksioul/2014-09-06-101902.jpg?dl=0
https://www.dropbox.com/s/dg1meg27ojsyvtc/2014-09-06-101846.jpg?dl=0
 
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  • #2
As drawn the circuit has no load between terminals A and B. A and B is where a load would be attached. The 5 k resistor between A and B is not a load resistor, it is part of the network to be analyzed so don't remove it!
 
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  • #3
Clearly a conceptual misunderstanding. Makes much more sense now. Thanks for pointing it out:)
 
  • #4
Second try

New procedure:
1) Left 5k resistor in as A and B have no load in between

2) Used three current loops I1, I2, I3 and calculated three currents using a system of equations.
Current equations
Currents solved
* I1=173.91 micro Amps
* I2= 8.69 micro Amps
* I3= 382.6 micro Amps

3) Found voltage drops over resistors
https://www.dropbox.com/s/xbx05mykzjvjw2y/2014-09-07-061535.jpg?dl=0

4) Used the voltage drops to find the Vth = 826mV
vthevenin

5) Now I am stuck. I have no idea how to find Rth for this circuit! Help!?

PS, sorry the webcam is garbage. My laptop was made ~200 yrs ago;)
 
  • #5
Check the sign on I2.

To find Rth start by suppressing all the voltage sources, then look for opportunities to combine serial and parallel combinations of resistors. I.e., reduce the circuit. Don't be fooled by the geometrical layout of the drawing --- pay attention to the actual connections of the components by identifying the nodes.
 
  • #6
thanks for the help gneill. I think I have it figured out. Rth = 1.884k and Vth = 826mV.

I have another conceptual question, if you don't mind. Thevenin vs Norton - I am comfortable with thevenin so I normally find the Vth and Rth and use Vth/Rth = In to then find the norton equivalent. Is there an advantage to one model over the other? Should I bother learning how to find Norton equivalents first?
 
  • #7
vikasagartha said:
thanks for the help gneill. I think I have it figured out. Rth = 1.884k and Vth = 826mV.
Those values look alright.

I have another conceptual question, if you don't mind. Thevenin vs Norton - I am comfortable with thevenin so I normally find the Vth and Rth and use Vth/Rth = In to then find the norton equivalent. Is there an advantage to one model over the other? Should I bother learning how to find Norton equivalents first?

Both equivalents have their advantages in certain situations. If you're given a circuit that already has current sources, direct reduction to a Norton equivalent may provide a more straightforward approach. Or, perhaps a circuit is just simpler to analyze with mesh equations, where one of the mesh currents is identified with the short circuit current that you're looking for. Then you may only need to find that single mesh current rather than solve for them all (Cramer's Rule rules!).

You should be able to work problems either way if for no other reason than you might be required to demonstrate it on an exam :wink:
 

FAQ: Thevenin Circuit: Help Me Verify My Solution

What is a Thevenin Circuit?

A Thevenin Circuit is a method used to simplify complex electrical circuits into a single voltage source and a single resistance. This allows for easier analysis and calculation of current and voltage in the circuit.

How is a Thevenin Circuit determined?

A Thevenin Circuit is determined by removing all the load components from the original circuit and calculating the equivalent resistance and voltage of the resulting circuit using Kirchhoff's laws and Ohm's law.

What is the purpose of verifying a Thevenin Circuit solution?

The purpose of verifying a Thevenin Circuit solution is to ensure that the calculated values match the actual values in the original circuit, and to check for any errors or mistakes in the calculation process. This helps to ensure accurate analysis and predictions for the circuit.

What are the steps for verifying a Thevenin Circuit solution?

The steps for verifying a Thevenin Circuit solution are as follows:
1. Remove all load components from the original circuit.
2. Determine the equivalent resistance of the resulting circuit.
3. Calculate the Thevenin voltage using Kirchhoff's laws and Ohm's law.
4. Reconnect the load components and calculate the current and voltage using the Thevenin voltage and equivalent resistance.
5. Compare the calculated values with the original values in the circuit to verify the solution.

What are some common errors when verifying a Thevenin Circuit solution?

Some common errors when verifying a Thevenin Circuit solution include incorrect calculation of the equivalent resistance, forgetting to reconnect the load components, and using the wrong values for the Thevenin voltage or current. It is important to double check all calculations and ensure that the correct values are used in the solution.

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