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Homework Statement
http://imageshack.us/a/img14/2387/homeworktest2prob2.jpg
a. Find the Thevenin equivalent circuit with respect to terminals a, B for the circuit.
b. Find also the Norton equivalent circuit with respect to the terminals A, B, for the circuit
Homework Equations
V = IR
current division, voltage division,
KCL, KVLThevenin procedure, Norton procedure.
The Attempt at a Solution
With the load cut out, 4Ω disappears and25V/5Ω + 3A = Vb/20Ω
100V + 60V = Vb
Vb = 160V, VTh = 160VI need help mainly with getting RThI don't know if I can just simplify the resistors from A to B with that current source (do I cut it out so it becomes an open circuit? I know you put a wire to short the 25V while doing it though).
Trying RTh = VTh/Ino instead, then a wire goes from a to b, then once I do that I try to use superposition (so might need help here with that to
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With the 3A cut out the equivalent R is 8.3Ω with 25V so I' = 3A
then with the 25V silenced the current is just I'' = 3A, right? Because that's the total current in?
So 3A + 3A = 6A
Ino = 6ASo for RTh I get 160V / 26.6A
= 6ΩBut I don't think it's correct.
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