Thin films: reflection between glass plates

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In the discussion about light reflection between parallel glass plates, participants analyze the conditions for intensified reflection due to interference. The key equations involve the thickness of the air film (d) and the refractive index (n) of the glass. The correct condition for maximum intensity is debated, with one participant suggesting 2d=mλ/n, emphasizing the role of the refractive index. Another contributor clarifies that the interference results from multiple reflections within the air film, highlighting the importance of understanding the setup and the behavior of light at the glass-air boundaries. The conversation centers on confirming the correct mathematical relationship for achieving bright fringes in this optical scenario.
vetgirl1990
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Homework Statement


Two parallel glass plates of index of refraction n
are separated by an air film of thickness d. Light of wavelength λ
in air, normally incident on the plates, is intensified
on reflection when, for some integer m

a) 2d=mλ
b) 2d=mλ/n
c) 2d=mnλ
d) 2d=(m+1/2)λ
e) 2d=mλ/2

Homework Equations


If only one ray is π shifted: 2nd=mλ (min), 2nd=(m+1/2)λ (max)

If both rays π shifted: 2nd=mλ (max), 2nd=(m+1/2)λ (min)

The Attempt at a Solution


I've attached a diagram of two different for how I picture light should be transmitted in this problem. I'm not sure which one would be a correct approach.

Going with the first diagram,
This would result in a net π shift, so it's conditions would be 2nd=mλ (min) and 2nd=(m+1/2)λ (max).

I chose answer (B) 2d=mλ/n, since the question asks for "intensity increase" so I am assuming it is asking about the condition for a bright fringe; and also because it's one of the only options that takes the index of refraction (n) into account.

I would just like to verify that my reasoning is correct.
 

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vetgirl1990 said:

Homework Statement


Two parallel glass plates of index of refraction n
are separated by an air film of thickness d. Light of wavelength λ
in air, normally incident on the plates, is intensified
on reflection when, for some integer m

a) 2d=mλ
b) 2d=mλ/n
c) 2d=mnλ
d) 2d=(m+1/2)λ
e) 2d=mλ/2

Homework Equations


If only one ray is π shifted: 2nd=mλ (min), 2nd=(m+1/2)λ (max)

If both rays π shifted: 2nd=mλ (max), 2nd=(m+1/2)λ (min)

The Attempt at a Solution


I've attached a diagram of two different for how I picture light should be transmitted in this problem. I'm not sure which one would be a correct approach.

Going with the first diagram,
This would result in a net π shift, so it's conditions would be 2nd=mλ (min) and 2nd=(m+1/2)λ (max).

I chose answer (B) 2d=mλ/n, since the question asks for "intensity increase" so I am assuming it is asking about the condition for a bright fringe; and also because it's one of the only options that takes the index of refraction (n) into account.

I would just like to verify that my reasoning is correct.

You are wrong . The light interference happens because of multiple reflection inside the thin air film between the thick glass plates. d is the thickness of the air film. n is the refractive index of the glass. You can consider the set-up that the air film is surrounded by glass and the light arrives to the glass-air boundary from glass, and reflected from the other side of the air film, from glass.

The
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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