Three charges are at the corners of an isosceles triangle

In summary, the conversation discusses the configuration of three charges in an isosceles triangle, with q1 = 5.05 uC and -q1 = 5.05 uC forming a dipole. The question asks for the magnitude and direction of the net force exerted by q2 = 8.50 uC on the dipole, as well as the magnitude and direction of the torque exerted by q2 on the dipole. The conversation also mentions the use of Coulomb's Law, and the need for a visual representation of the charges and forces involved in the problem.
  • #1
knv
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1. Three charges are at the corners of an isosceles triangle as shown in the figure. The +q1 = 5.05 uC and -q1 = 5.05 uC charges form a dipole.

A) Find the magnitude and direction of the net force that the q2 = 8.50 uc charge exerts on the diple.

B) For an axis perpendicular to the line connecting he two charges of the diple at its midpoint perpendicular to the plane of the paper, find the magnitude and direction of the torque exerted on the dipole by the q2 = 8.50 uC.




2. I know we use Coulomb's Law which is F = kq1q2/ r2



3. I need help starting this problem and an explanation so I can understand it. i do not need the answer, just help setting up the problem
 
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  • #2


Draw a picture that shows the three charges and draw the forces exerted by q2 both at q1 and -q1.

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FAQ: Three charges are at the corners of an isosceles triangle

What is an isosceles triangle?

An isosceles triangle is a triangle with two equal sides and two equal angles.

How are the charges arranged in this scenario?

The charges are at the corners of the triangle, with each charge located at a different corner.

What is the significance of the charges being at the corners of an isosceles triangle?

This arrangement creates a symmetrical distribution of charges, which can result in a net electric force of zero.

What is the relationship between the charges in this scenario?

Since the triangle is isosceles, the two equal charges at the base of the triangle will have a greater repulsive force on the charge at the apex, which is opposite in polarity.

How does the distance between the charges affect the net electric force?

The net electric force between the charges will decrease as the distance between them increases, following the inverse square law.

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