- #1
Lucaburra
- 3
- 0
Homework Statement
Force A 250 degrees @ 200 N
Force B 150 degrees @ 300 N
Force C 50 degrees @ 400 N
mass = 40kg
mew = .14
what is acceleration
Homework Equations
Fa^2 = Fy net^2 x Fx net^2
Fn = Fg
Ff = Fn x mew
Fnet = Fa - Ff
F= ma
The Attempt at a Solution
Fax=Cos 20 (200) = -187.93
Fay = Sin 20 (200) = -68.40
Fbx = Sin 30 (300) = 150
Fby = Cos 30 (300) = -259.81
Fcx = Cos 50 (400) = 257.11
Fcy = Sin 50 (400) = 306.42
Fx net = 219.18 N
Fynet = -21.79 N
Fa^2 = Fxnet^2 + Fynet^2
Fa^2 = 219.18^2 + -21.79^2
Fa^2 = 48039.87 + -474.80
Fa^2 = 47565.07
Fa = 218.09 N
Fn = 9.81 m/s^2 x 40Kg = 392.40N
Ff = Fn (mew) = 392.40N (.14) = 54.94 N
Fnet = Fa - Ff = 218.09 - 54.94 = 163.15 N
a = F/m = 163.15/40 = 4.08 m/s
I'm just not sure I've done this correct