- #1
Ecterine
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A ball is thrown horizontally from the top of a building and lands a distance d from the foot of the building after having been in the air for a time T and encountering no significant air resistance.
If the building were twice as tall, the ball would have
a) landed a distance 2d from the foot of the building
b) been in the air a time 2T
c) been in the air a time T squareroot2
d) reached the ground with twice the speed it did from the shorter building
x=x0 + v0xt + 1/2at^2
vx = v0xt +axt
and vx^2 = V0x^2 +2a (xf - xi)
Are, I think, the right equations. I don't know what to do though :(
If the building were twice as tall, the ball would have
a) landed a distance 2d from the foot of the building
b) been in the air a time 2T
c) been in the air a time T squareroot2
d) reached the ground with twice the speed it did from the shorter building
x=x0 + v0xt + 1/2at^2
vx = v0xt +axt
and vx^2 = V0x^2 +2a (xf - xi)
Are, I think, the right equations. I don't know what to do though :(