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Ajit Kumar
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If an object is thrown upwards with escape velocity, will it orbit the earth?
For a body launched from the surface of the Earth the only possibility for a circular orbit is a horizontal launch with a speed equal to escape velocity divided by the square root of two. Any other direction and the orbit will intersect with the surface of the Earth. Any higher velocity and the orbit will fail to be circular. It will rise above the surface of the earth. Any lower velocity and the orbit will fail to be circular. It will fall below the surface of the earth.Ajit Kumar said:Will a body projected with a speed less than the escape velocity may orbit the Earth in circular path?
A thrown object refers to any object that is given an initial velocity and then allowed to move under the influence of gravity. This includes objects thrown by hand, launched by a machine, or even objects in orbit around a larger body.
Escape velocity is the minimum velocity required for an object to escape the gravitational pull of a larger body, such as the Earth. For Earth, this velocity is approximately 11.2 km/s or 25,000 mph.
The escape velocity of an object is directly proportional to the mass of the body it is escaping from. This means that the larger the mass of the body, the greater the escape velocity required for an object to break free from its gravitational pull.
Yes, an object with a lower escape velocity can achieve orbit around a larger body by balancing its gravitational pull with its centripetal force. This means that the object will continuously fall towards the larger body, but its forward motion will keep it in a curved path around it.
Some common examples of objects being thrown from Earth's surface include rockets, baseballs, frisbees, and even paper airplanes. Satellites and spacecrafts are also launched from Earth's surface using powerful machines to achieve the necessary escape velocity.