- #1
greg_rack
Gold Member
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- Homework Statement
- A charged capacitor of potential ##V=20V## is connected to a resistance ##R=1k\Omega##.
While discharging, at time ##t_{1}=0.12s## the charge is ##q_{1}=40\mu C##, whilst at time ##t_{2}=0.20s## the charge is ##q_{2}=5.4\mu C##. Determine:
-the time constant of the circuit;
-the charge on the capacitor at instant ##t_{0}=0s##;
-the capacity of the capacitor.
- Relevant Equations
- ##q=CV##
Discharge function: ##q(t)=q_{0}e^{-\frac{t}{\tau}}##
So, the only thing which came to my mind in order to solve this problem was actually to write down the equations using the discharge function, being given two instants and their corresponding charges... but doing so I'm unable to find anything.
Ideally, I'd say I should find the time constant ##\tau##, then the capacity, and lastly the maximum charge at the beginning of the process.
Ideally, I'd say I should find the time constant ##\tau##, then the capacity, and lastly the maximum charge at the beginning of the process.