Time Dependent Perturbation Theory - Klein Gordon Equation

In summary, the assumption is that the second order derivative of a(t) with respect to time is small, and this allows us to simplify the equation for the output wavefunction.
  • #1
Sekonda
207
0
Hey,

I'm struggling to understand a number of things to do with this derivation of the scattering amplitude using time dependent perturbation theory for spinless particles.

We assume we have some perturbation 'V' such that :

[tex]\left ( \frac{\partial^2 }{\partial t^2}-\triangledown ^2 + m^2 \right )\psi = \delta V\psi[/tex]

We also assume plane wave solutions of the wavefunction such that the input wavefunction is:

[tex]\psi _{in}=\psi _{i}(x)e^{-iE_{i}t}[/tex]

A single eigenwavefunction of the wavefunction psi. This input interacts and we get an output wavefunction which can be expanded like so:

[tex]\psi _{out}=\sum_{n}a_{n}(t)\psi _{n}(x)e^{-iE_{n}t}[/tex]

We substitute this output wavefunction into the perturbed Klein Gordon equation above and attain, (by assuming the second derivative of a(t) with respects to time is small):

[tex]\frac{\partial^2 }{\partial t^2}\sum_{n}a_{n}(t)\psi _{n}(x)e^{-iE_{n}t}=\delta V\sum_{n}a_{n}(t)\psi _{n}e^{-iE_{n}t}[/tex]

Upon assuming the second derivative of a(t) is small we obtain the simplified equation:

[tex]-2i\sum_{n}\dot{a}_{n}(t)\psi _{n}(x)e^{-iE_{n}t}=\delta V\sum_{n}a_{n}(t)\psi _{n}e^{-iE_{n}t}[/tex]

Though I'm not exactly sure why all these terms cancel... Nonetheless, to specify a value within the sum we use the orthogonality of wavefunctions - we want to attain the 'final' wavefunction and amplitude (denoted by subscript 'f') and so we multiply both sides of the above equation by:

[tex]\int_{-\infty }^{\infty }d^{3}x\psi_{f}^{*}[/tex]

We then attain this equation upon use of orthogonality:

[tex]-2iE_{f}\dot{a}_{f}e^{-iE_{f}t}=\int_{-\infty }^{\infty }d^{3}x\psi _{f}^{*}\delta V\sum_{n}a_{n}(t)\psi _{n}e^{-iE_{n}t}[/tex]

We then simplify by saying at t=0, all a(t)=0 apart from the initial a(0)=1 (so essentially we have one eigenwavefunction coming in) - this holds true for small 't'. The equation then becomes:

[tex]-2iE_{f}\dot{a}_{f}e^{-iE_{f}t}=\int_{-\infty }^{\infty }d^{3}x\psi _{f}^{*}\delta V \psi _{i}e^{-iE_{i}t}[/tex]

to

[tex]\dot{a}_{f}(t)=\frac{i}{2E_{f}}\int_{-\infty }^{\infty }d^{3}x\psi _{f}^{*}\delta V \psi _{i}[/tex]

and finally attaining solution:

[tex]a_{f}(t)=\frac{i}{2E_{f}}\int_{-\infty }^{\infty }d^{4}x\psi _{f}^{*}\delta V \psi _{i}[/tex]

(the d4x including the time differential)

Now I'm unsure of a number of things including the output wavefunction form - I think it's just a sum of wavefunctions related to the input but the input is just a single wavefunction?

I'm unsure on why terms cancel in the assumption that the second derivative of 'a' with respects to time is small, though I will try doing the differentiation now and see if I can do it.

Basically, I'd be grateful if someone could check that this derivation follows through and if someone could explain why the assumptions have been made that'd be great.

Thanks guys,
SK
 
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  • #2
The jump from the 4th to the 5th equation is confusing me, upon applying the time derivative and laplacian operator we attain a number of expressions that disappear but I'm not sure why. Can someone explain why these terms cancel or =0?

Thanks
 
  • #3
They just disappear because apart from an,the ψ satisfies the homogeneous part,which will be equal to zero in absence of any potential.
 
  • #4
So am i correct in thinking that the perturbation is instantaneous and so the outgoing wavefunction can be treated as a free particle and so solves the free Klein-Gordon equation?

Thanks
 
  • #5
Sekonda said:
So am i correct in thinking that the perturbation is instantaneous and so the outgoing wavefunction can be treated as a free particle and so solves the free Klein-Gordon equation?

Thanks
of course,that is the lowest order approximation to treat the outgoing wavefunction as a free particle,that is what is done in general theory.But I do think that perturbation must be treated adiabatic in character.
 
  • #6
Thanks, that's essentially what my professor said today - I was incorrect in describing the perturbation as instantaneous.

Cheers!
 
  • #7
Dear i wish to know what is the validity of assumption that the second order derivative of a(t) is neglected. Kindly clarify the issue.
 

FAQ: Time Dependent Perturbation Theory - Klein Gordon Equation

What is Time Dependent Perturbation Theory?

Time Dependent Perturbation Theory is a mathematical technique used in quantum mechanics to study the behavior of a system under the influence of an external perturbation. It allows us to calculate the changes in the system's energy levels and wave functions over time.

What is the Klein Gordon Equation?

The Klein Gordon Equation is a relativistic wave equation that describes the behavior of spinless particles such as mesons. It is a generalization of the Schrödinger equation and takes into account both time and space dimensions.

How is Time Dependent Perturbation Theory applied to the Klein Gordon Equation?

Time Dependent Perturbation Theory is used to solve the Klein Gordon Equation by treating the external perturbation as a small correction to the original equation. This allows us to calculate the changes in the particle's energy and wave function due to the perturbation.

What are the limitations of Time Dependent Perturbation Theory?

One major limitation of Time Dependent Perturbation Theory is that it assumes the perturbation is small, which may not always be the case in real-world systems. Additionally, it does not take into account effects such as particle creation and annihilation, which are important in high-energy physics.

What are some applications of Time Dependent Perturbation Theory - Klein Gordon Equation?

Time Dependent Perturbation Theory - Klein Gordon Equation has various applications in quantum field theory, particle physics, and condensed matter physics. It is used to study phenomena such as atomic and molecular spectra, scattering processes, and particle interactions. It also plays a crucial role in understanding the behavior of systems under the influence of external fields or forces.

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