- #36
Dead Boss
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Doesn't Michelson-Morley experiment confirm length contraction?
NO, at-least not in the real sense, as the Time Dilation of Muons.Dead Boss said:Doesn't Michelson-Morley experiment confirm length contraction?
This is all about the strange fact that the spaceships must have unequal accelerations in order for the strings to stay whole. It has no relevance to your muon experiment.universal_101 said:Are you suggesting that, the string in the Bell's spaceship paradox breaks because of acceleration, and not because of relative velocity !
The ages of the twins is equal to the proper time measured along their worldlines. This is a geometric invariant. All observers agree on those numbers. Time dilation is something that appears when the time in one reference frame is transformed to the time in a different frame.If that is the case, then it means that younger twin returns with the same difference in his age w.r.t the other Twin, No matter with respect to whom it is moving at what speed.Mentz114 said:No it is not. That is called differential ageing and is a physical and invariant effect. Time dilation is a coordinate effect.
It is the proper length of each worldline. It is not frame dependent.That means, that only the relative speed of the traveling Twin w.r.t the staying Twin, is what accounts for the difference in the age.
See above.... I'm a bit confused about the definition of Time Dilation itself then.
Each twin has his own worldline which gives the elapsed time irrespective of what the other one is doing.Since you are suggesting that difference in age is frame invariant, don't you think it seems pretty preferential to the Frame w.r.t which the traveling Twin is moving !
universal_101 said:Since, any observer just by mere moving w.r.t the object cannot effect what happens to the Object, by that same analogy, how can one understand the breaking of the string in Bell's spaceship Paradox, if the string cannot be affected by the motion of the observer.
Mentz114 said:This is all about the strange fact that the spaceships must have unequal accelerations in order for the strings to stay whole. It has no relevance to your muon experiment.
Mentz114 said:The ages of the twins is equal to the proper time measured along their worldlines. This is a geometric invariant. All observers agree on those numbers. Time dilation is something that appears when the time in one reference frame is transformed to the time in a different frame.
Unfortunately, I am unable to understand physics in abstract form, please let's just stick to the length contraction, Time Dilation, velocity addition etc.Mentz114 said:It is the proper length of each worldline. It is not frame dependent.
Mentz114 said:Each twin has his own worldline which gives the elapsed time irrespective of what the other one is doing.
Yes.universal_101 said:In the end, it means that the younger Twin stays younger by the same amount, No matter which frame we observe his motion from. Please reply, yes or no, because I'm getting confused.
That is a pity. The best thing about SR is the fact that all obervers agree about elapsed time on clocks. If that was not so, then 'time-bomb' paradoxes appear.Unfortunately, I am unable to understand physics in abstract form, please let's just stick to the length contraction, Time Dilation, velocity addition etc.
The distance that cosmic muons descend through the atmosphere is a test of length contraction and time dilation. In the muon frame the half-life is not affected but the distance is contracted. From the Earth frame the distance is the same but the half life is longer. Beautiful symmetry ? ( This was pointed out more than once in previous replies).Yes, this is what I learned till now, but all this suggests there should be a real length contraction in the sense, that we can measure it, just like Time Dilation of Muons.
PeterDonis said:The string isn't broken by "motion" with respect to some arbitrary observer. The string is broken because the two ends of it are physically attached to spaceships that stretch the string until it breaks. If the string ends weren't attached to the spaceships then the string wouldn't break.
You can express this condition in a frame-invariant way by saying that the ratio of "actual length" to "unstressed length" for the string increases until it exceeds the string's tensile strength, at which point the string breaks.
It's true that how you "interpret" why the string breaks can depend on the motion of the "observer". With respect to the "lab" frame, the frame in which the spaceships are initially at rest and in which they follow identical "acceleration profiles", the string breaks because its "unstressed length" gets smaller and smaller due to "length contraction", while its "actual length" stays constant (because the ends of the string are physically attached to the spaceships, which remain a constant distance apart in this frame). With respect to the "spaceship frame", however, the string's "unstressed length" stays constant, while its "actual length" gets larger and larger because the spaceships are moving apart in this framem, and therefore the string ends are too. (Actually there isn't a single "spaceship frame", but we can use either the front spaceship or the rear spaceship's frame and get the same result.)
So whether or not "length contraction" is "real" depends on whether you are looking at motion relative to some arbitrary "observer", or whether you are looking at actual, physical constraints imposed by the actual, physical conditions of the problem (like the string ends being physically attached to the spaceships). I recommend sticking to the latter. Similar remarks would apply to "time dilation" as in the muon experiment.
Mentz114 said:Yes.
Mentz114 said:That is a pity.
Mentz114 said:The distance that cosmic muons descend through the atmosphere is a test of length contraction and time dilation. In the muon frame the half-life is not affected but the distance is contracted. From the Earth frame the distance is the same but the half life is longer. Beautiful symmetry ? ( This was pointed out more than once in previous replies).
The easiest way to approach this problem is to write the radioactivity law in a relativistically invariant form. Specifically:universal_101 said:Alright, here is what I was able to get as calculation,
Consider the length if the accelerator to be L, initial number of Muons be x, rest frame Half-Life of Muons be [itex]\lambda[/itex], and for the simplicity of the calculations I would assume that Muons are traveling with speed v0 in the Lab's Frame.
Now to calculate the number of Muons reaching the other End, from the Frame of the Lab's Frame. The time of flight of the Muons would be [itex]\frac{L}{v_0}[/itex], Now during this Time we have to include the Time Dilation and radioactivity law.
Since, [itex]\ N = x e^{-\lambda t}[/itex],
You haven't written your equation in terms of coordinates, so you really can't use the Lorentz transform since the Lorentz transform transforms between different coordinate systems. That said, this is a correct expression in the accelerator's frame except that you are missing a square on v0.universal_101 said:Therefore, the number of Muons reaching the other End should be,
[itex]\ y = x e^{-\frac{\lambda}{\sqrt{1 - \frac{v_0}{c^2}}} (\frac{L}{v_0})}[/itex],
Now, to transform these sets of Equations to another Frame, we should use Lorentz transformations, which says , all the Lengths along the direction of motion would be contracted and velocities need to be added relativistically.
This expression is incorrect because the time that it takes for the muons to reach the detector is not equal to L_r/v_r in any frame except the accelerator frame. For example consider v=-v0, i.e. v_r=0 or the muon's rest frame. In this frame, since the muons are at rest, the formula L_r/v_r predicts that the time to reach the detector is infinite. However, the detector is moving towards the muons and therefore the muons reach the detector in a finite amount of time (specifically L_r/v0).universal_101 said:Therefore let's assume a simple Frame which is moving along the length of the accelerator and whose speed w.r.t the Lab's Frame is 'v', and as viewed from the Lab's Frame this Frame is moving opposite to the direction of motion of Muons.
Now, speed of Muons w.r.t this Frame will be [itex]v_r = ({v + v_0})/({1 + \frac{v_0 v}{c^2}})[/itex] , the length of the accelerator would be, [itex]L_r = L (\sqrt{1 - v^2/c^2})[/itex] , where as the Time Dilation of half-lifr of Muons would be, [itex]\lambda_r = \lambda/\sqrt{1 - (v_r)^2/c^2}[/itex]
Putting these values in the radioactivity law will give the calculation for the number of muons reaching the other end as observed by this new Frame.
That is, [itex] y_r = x e^{-(\lambda_r)({L_r}/{v_r})} [/itex] ,
The number of muons depends on the decay rate and the decay time, both of which vary relativistically. The net result is that all frames agree on the number of muons that arrive, although they may disagree about the rate that they are decaying and how long it takes them to reach the detector.universal_101 said:That is, I think that it is the number of Muons reaching the other End which specifies the Time Dilation.
Jonathan Scott said:Getting back to the original subject...
The way to calculate how many muons survive is to calculate what the time between the two events looks like from the point of view of an observer on the muon, which is the proper time that elapses along that path. The result is invariant, which means it is the same regardless of the frame of the reference of the observer. Time dilation and length contraction can be used to transform the description from one observer's frame to another, but the proper time is an invariant quantity.
Jonathan Scott said:Lorentz velocity transformations between space and time (known as "boosts") are in many ways similar to rotations in space (apart from a somewhat confusing minus sign, which relates to the fact that the rotation "angle" is imaginary). In space, one observer's (x,y,z) measurements between two events may be different from another, but the distance between the events is not affected by the direction of the axes. Similarly, in Lorentz transformations, different observers may measure different time and space displacements, but when they compute the magnitude of the total straight-line displacement between two events, or the length of a specific path connecting two events, everyone gets the same value.
DaleSpam said:This expression is incorrect because the time that it takes for the muons to reach the detector is not equal to L_r/v_r in any frame except the accelerator frame. For example consider v=-v0, i.e. v_r=0 or the muon's rest frame. In this frame, since the muons are at rest, the formula L_r/v_r predicts that the time to reach the detector is infinite. However, the detector is moving towards the muons and therefore the muons reach the detector in a finite amount of time (specifically L_r/v0).
I would recommend using the invariant form of the equation. It solves all of the hassles immediately.
Unless the Earth frame sees a time dilation, and the muon frame sees length contraction there will be a paradox. So if time dilation is 'real', so is length contraction.universal_101 said:So, does that mean we have an experimental confirmation of Length contraction, by the Time Dilation of muons,
It's a coordinate effect. I don't know if that makes it real.By the way, you never responded on the apparent or real length contraction, which I'm struggling with.
Mentz114 said:Unless the Earth frame sees a time dilation, and the muon frame sees length contraction there will be a paradox. So if time dilation is 'real', so is length contraction.
Mentz114 said:It's a coordinate effect. I don't know if that makes it real.
The Lorentz transform can be used to explain experimental observations because the laws of physics are invariant under Lorentz transforms.universal_101 said:But if Lorentz transformation is just a co-ordinate transform, then how can it support/explain/justify the real events like Time Dilation of Muons and a real Length contraction in order to justify the Time Dilation of Muons themselves.
You can do a coordinate transform to any frame you like. It doesn't have to be the rest frame of the muons. I just picked that frame because it made the mistake very obvious.universal_101 said:Besides, I included every thing you asked me to include in my calculations, but in the end what you are suggesting is, just do a co-ordinate transform for the reference frame of Muons.
DaleSpam said:This expression is incorrect because the time that it takes for the muons to reach the detector is not equal to L_r/v_r in any frame except the accelerator frame. For example consider v=-v0, i.e. v_r=0 or the muon's rest frame. In this frame, since the muons are at rest, the formula L_r/v_r predicts that the time to reach the detector is infinite. However, the detector is moving towards the muons and therefore the muons reach the detector in a finite amount of time (specifically L_r/v0).
I would recommend using the invariant form of the equation. It solves all of the hassles immediately.
Mentz114 said:...Special relativity predicts correctly what happens, which is support for the idea of time dilation/length contraction, but I don't believe those phenomena can be directly observed. I think you made this point earlier.
Mentz114 said:They must belong to that class of things which are part of successful theories but cannot be directly observed. Like the wave function, or the vector potential.
Mentz114 said:Whether something which cannot be directly observed is 'real' may just be an argument over words.
DaleSpam said:The Lorentz transform can be used to explain experimental observations because the laws of physics are invariant under Lorentz transforms.
DaleSpam said:You can do a coordinate transform to any frame you like. It doesn't have to be the rest frame of the muons. I just picked that frame because it made the mistake very obvious.
I must have missed this. How ?universal_101 said:Agreed, but Time Dilation of Muons can be directly observed.
Mentz114 said:Whether something which cannot be directly observed is 'real' may just be an argument over words.
universal_101 said:Agreed, but Time Dilation of Muons can be directly observed.
Mentz114 said:I must have missed this. How ?
Actually, it is the approaching speed which is important.universal_101 said:But soon after, I realized that [itex]v_r[/itex], is the relative velocity of the Muons w.r.t the accelerator, and therefore a invariant, which implies, [itex]v_r = v_0[/itex] simply.
universal_101 said:It is the Explanation of time dilation of muons ... that necessitated the introduction of ... length contraction, to which we don't have any experimental evidence...
universal_101 said:An object does not change it's state just because a observer is moving relative to it.
DaleSpam said:Actually, it is the approaching speed which is important.
Since you are assuming what have happened so far, can I safely assume that you did not read the previous discussions.Samshorn said:I assume you've been told many times that that's completely false,
I agree, that Fitzgerald introduced/coined the term Length contraction to explain the results of MMX. But again, we are not discussing when was it first proposed.Samshorn said:...Historically, length contraction was introduced by Fitzgerald and Lorentz in order to account for the results of the Michelson-Morley experiment, long before anyone ever dreamed of muons or even special relativity.
MMX was about the light and its properties, whereas, Time Dilation of Muons has nothing to do with Light and it's properties because if it does, there are contradictions of Logic. Again for the later part you need to read the previous posts.Samshorn said:And of course the MM experiment along with all other failed attempts to measure absolute velocity and all the experimental demonstrations of the invariance of light speed, and indeed the Lorentz invariance of all physical phenomena in terms of standard inertial coordinates, collectively are irrefutable experimental evidence of both length contraction and time dilation.
Samshorn said:Also, length contraction emerges from Lorentz's theorem of corresponding states based on the already-known laws of electrodynamics, and of course Lorentz always stressed the physical reality of (and necessity of) this contraction for active transformations.
Samshorn said:You need to distinguish between intrinsic and extrinsic state variables, and between passive and active transformations.