Time for falling down the incline (Rotating Solid Cylinder)

In summary: The cause of the downward force would be the component of the weight of the cylinder down the incline. This force was initially balanced by the normal force from the incline, but once the cylinder stops spinning and starts rolling, the normal force decreases and the component of weight down the incline becomes the net downward force causing the cylinder to move down. In summary, the question asks for the time it takes for a solid cylinder to start moving down an incline after being spun and placed on it. To solve this, the applied torque due to friction must be calculated and the time it takes for that torque to drain the initial angular momentum and stop spinning must be found. The equations used in the attempt at a solution were incorrect and the correct
  • #36
ehild said:
there is a mistake in your equation.

ehild
That's an alpha (α), not an a.
 
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  • #37
Vibhor said:
Are you suggesting that we should assume this constraint and from this we find the static frictional force F and then prove that this F < μsN . Thereby concluding that since the frictional force required for rolling without slipping is less than μsN , rolling without slipping occurs .

But if we had obtained F > μsN , we could have argued that slipping does occur as friction is not sufficient .

Am I understanding it correctly ?
Yes.
 
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