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Curiosity_0
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We know that if a projectile is thrown vertically, there will be a brief time when it momentarily stops. Can we calculate this brief moment?
It's zero seconds. It's the same for any other velocity on its trajectory.Curiosity_0 said:We know that if a projectile is thrown vertically, there will be a brief time when it momentarily stops. Can we calculate this brief moment?
As others have said, the velocity is zero only instantaneously. These plots of the vertical motion of a projectile should help. See how the acceleration due to gravity is a constant negative value (-g)?, and how the velocity decreases linearly from the initial ##v_0## down through zero to end up being ##-v_0## when the projectile impacts the ground?Curiosity_0 said:We know that if a projectile is thrown vertically, there will be a brief time when it momentarily stops. Can we calculate this brief moment?
It will stop at a particular clock-reading, but that clock-reading lasts for zero time.Curiosity_0 said:We know that if a projectile is thrown vertically, there will be a brief time when it momentarily stops. Can we calculate this brief moment?
We 'think' we know that. Reasonable enough because things happen pretty slowly at the high point it would really boil down to how quickly and accurately we could actually measure that velocity. Zero velocity is actually no more special than +1m/s or -1.05m/s. This was a problem for the old Physicists until the concepts involved in Differential Calculus were introduced. The theory is that you consider a smaller and smaller interval between two (imagined) measurements the limit as the interval approaches zero is the 'true' value of the velocity.Curiosity_0 said:We know that if a projectile is thrown vertically, there will be a brief time when it momentarily stops. Can we calculate this brief moment?
The time for which a vertical projectile stays motionless in midair can be calculated using the formula t = (2v0sinθ)/g, where t is the time, v0 is the initial velocity, θ is the angle of projection, and g is the acceleration due to gravity.
The time for which a vertical projectile stays motionless in midair is affected by the initial velocity, angle of projection, and acceleration due to gravity. Other factors such as air resistance and the shape of the projectile may also have an impact.
The angle of projection has a direct impact on the time for which a vertical projectile stays motionless in midair. The higher the angle of projection, the longer the projectile will stay in the air before falling back down. This is because a higher angle results in a longer horizontal distance traveled, which takes more time.
No, the time for which a vertical projectile stays motionless in midair cannot be greater than the time it takes to reach the maximum height. This is because the projectile must reach its maximum height before falling back down, and the time it takes to reach the maximum height is the longest time the projectile will stay in the air.
Air resistance can have a significant impact on the time for which a vertical projectile stays motionless in midair. The presence of air resistance can decrease the time by slowing down the projectile's speed and causing it to fall back to the ground sooner. However, for short distances and low velocities, the effect of air resistance may be negligible.