- #1
Mohanraj S
- 2
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If equation of motion(K-G Eqn.,) follows,
∂μ∂μΦ+m2Φ=ρ
where 'ρ' is point source at origin.
How time independent form of above will become,
(∇2-m2)Φ(x)=gδ3(x)
where g is the coupling constant,
δ3(x) is three dimensional dirac delta function.
∂μ∂μΦ+m2Φ=ρ
where 'ρ' is point source at origin.
How time independent form of above will become,
(∇2-m2)Φ(x)=gδ3(x)
where g is the coupling constant,
δ3(x) is three dimensional dirac delta function.
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