Time-integral of a voltage function?

In summary, the voltage is a measure of the charge flowing through a membrane, the time integral of current is a measure of the potential energy dissipated in the duration of the wave, and the second derivative of the voltage is a measure of the current flowing at a given point in time.
  • #1
Dan Kanak
3
0
Hi, this is my first post. I've not taken a calculus-based physics course yet so these may be rather naive questions. I'm looking at field potential recordings in rat hippocampi. My aim is to characterize the large-amplitude spontaneous waves seen in the data. I was hoping someone with a stronger physics background would explain 1) the meaning of the time integral of a voltage function and 2) the meaning of the second derivative of a voltage function.
As to the integral, it seems to me that this would be a measurement of ion flux across the membranes of the population of neurons in vicinity of the recording electrode. Also, I'm pretty sure that the first derivative of a voltage function is current but is there any meaning to its second derivative. Thank you for your help,

Dan
 
Physics news on Phys.org
  • #2
Are the voltage measurements transmembrane potentials or are they more like EEG lead voltages? I took a 1 semester neurophysiology course a long time ago, but I only remember the transmembrane stuff, not the more macroscopic stuff. And even the transmembrane stuff is a little hazy.

If you can assume a constant resistance then the voltage is proportional to current and the time integral of current is charge. The resistance of a membrane is definitely not constant, when the membrane ion channels are closed the resistance is very high but when they are open it is relatively low. But maybe it is a reasonable approximation for EEG leads.

Similarly, if you have a constant capacitance then the first derivative of your voltage is proportional to the current. I think that constant capacitance is probably a better approximation than constant resistance, but I am not certain.

I don't know of any significance to the second time derivative of the voltage. The frequencies involved are low enough that I think it is safe to neglect the magnetic fields and EM radiation generated by these voltages. In any case, it would be a really noisy value, so probably of limited usefulness even if there were some great physical significance.
 
  • #3
Thanks for replying Dale.

We record local field potentials in brain slices; the electrodynamic principles are probably similar to EEG recordings but I don't know for sure. The waves I'm interested in reflect the synchronous discharging of a whole population of neurons. That they're negative-going reflects the increased Na+ influx. This means that membrane conductance, resistance as well as capacitance are variable.

Other groups have reported using an estimate of the second derivative as a means of identifying "significant" waves in the data. Maybe the only significance is that it's a measure of the magnitude of the slope at a given time?

As to the time integral of current measuring charge, that's makes sense since current is a rate but resistance changes in our case. The electrochemical gradient across the membrane is the potential energy that drives ion flux. As you said, when ion channels open it's like discharging a capacitor and ions flow down their potential energy gradients (changing direction at their reversal potentials). Is the time integral of the wave then equivalent to amount of energy dissipated in the duration of the wave? I'm confused!
 
  • #4
Since resistance and capacitance are time varying I do not think you can read anything physical into the integrals or derivatives of the voltage. If you really need a physical interpretation then you will need to measure current as well.
 

FAQ: Time-integral of a voltage function?

What is the time-integral of a voltage function?

The time-integral of a voltage function is a mathematical operation that calculates the area under the curve of a voltage function over a specific period of time. It is used to measure the total change in voltage over time.

How is the time-integral of a voltage function represented?

The time-integral of a voltage function is typically represented by an uppercase letter "V" with a bar on top, followed by a time interval in parentheses. For example, ∫V(t)dt represents the time-integral of voltage function V over time interval t.

What are some real-world applications of the time-integral of a voltage function?

The time-integral of a voltage function is commonly used in fields such as electrical engineering and physics to analyze and understand the behavior of electrical circuits and devices. It is also used in signal processing to analyze and filter signals.

How is the time-integral of a voltage function calculated?

The time-integral of a voltage function is calculated by dividing the voltage function into small time intervals, calculating the area under the curve for each interval, and then summing up all the areas to find the total time-integral. It can also be calculated using mathematical integration techniques.

What is the difference between the time-integral of a voltage function and the derivative of a voltage function?

The time-integral of a voltage function calculates the total change in voltage over time, while the derivative of a voltage function calculates the rate of change of voltage with respect to time. In other words, the time-integral gives the total amount of change, while the derivative gives the rate at which the change is occurring.

Similar threads

Replies
8
Views
35K
Replies
2
Views
5K
Replies
4
Views
4K
Replies
2
Views
4K
Replies
8
Views
20K
Replies
6
Views
2K
Back
Top