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Homework Statement
A cyclindrical pipe of length 29.5 cm closed at one end resonates with a tuning fork of frequency 864 Hz. Then mode of vibration of air in the pipe is(Velocity of sound in air=340m/s):
The attempt at a solution
V=Velocity, n=Frequency
If l1 is the first resonating length
then l1 = V/4n = 340/(4X864) = 0.0983m = 9.83 cm
Also, l2 is second resonating length
l2 = 3V/4n = 3 X 9.83 = 29.51 cm
This is the maximum resonating length possible in the pipe. Therefore the mode of vibration is 2.
But the answer given is 3! Please help...
A cyclindrical pipe of length 29.5 cm closed at one end resonates with a tuning fork of frequency 864 Hz. Then mode of vibration of air in the pipe is(Velocity of sound in air=340m/s):
The attempt at a solution
V=Velocity, n=Frequency
If l1 is the first resonating length
then l1 = V/4n = 340/(4X864) = 0.0983m = 9.83 cm
Also, l2 is second resonating length
l2 = 3V/4n = 3 X 9.83 = 29.51 cm
This is the maximum resonating length possible in the pipe. Therefore the mode of vibration is 2.
But the answer given is 3! Please help...