To find the expectation of the greater of X and Y

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In summary, the conversation is about proving the expectation of the greater of X and Y when (X, Y) has a bivariate normal distribution with zero means and unit variances and a given correlation coefficient \rho. The general formula for this expectation can be derived, and the speaker has asked for clarification and more information before proceeding with the explanation.
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Suvadip
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If \(\displaystyle (X, Y)\) has the normal distribution in two dimensions with zero means and unit variances and correlation coefficient \(\displaystyle \rho\), then to prove that the expectation of the greater of X and Y is \(\displaystyle \sqrt{(1-\rho)\pi}\).

How to proceed with it? Help please.
 
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What exactly do you mean with the greater of $X$ and $Y$? I suppose $\max\{X,Y\}$?

When $(X,Y)$ has a bivariate normal distribution it follows that $X$ and $Y$ are normally distributed (in this case with zero means and unit variances). The correlation coefficient describes the dependency structure between $X$ and $Y$. If $X$ and $Y$ are independent, in other words $\rho = 0$, then it's not very difficult to derive that
$$\mathbb{E}[\max\{X,Y\}] = \frac{1}{\sqrt{\pi}}$$.

However when $\rho \neq 0$ then it's harder to derive an expression for the expectation but there's a general formula. So before I proceed I have three questions: Do you want a full derivation of the general formula? Where does this problem come from? What have you already tried?
 

FAQ: To find the expectation of the greater of X and Y

What is the formula for finding the expectation of the greater of X and Y?

The formula for finding the expectation of the greater of X and Y is E[max(X,Y)] = ∫∫ max(x,y) f(x,y) dxdy, where f(x,y) is the joint probability density function of X and Y.

How do you interpret the expectation of the greater of X and Y?

The expectation of the greater of X and Y represents the average value of the larger value between X and Y. It can also be thought of as the expected maximum outcome between the two variables.

Can the expectation of the greater of X and Y be negative?

No, the expectation of any random variable cannot be negative. It represents the average value of the variable, which by definition cannot be negative.

How is the expectation of the greater of X and Y calculated for discrete variables?

For discrete variables, the expectation of the greater of X and Y can be calculated by summing the products of the larger value between X and Y and their corresponding probabilities.

Is the expectation of the greater of X and Y affected by the correlation between X and Y?

Yes, the expectation of the greater of X and Y is affected by the correlation between the two variables. A higher positive correlation would result in a higher expectation, while a negative correlation would result in a lower expectation.

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