Torque on a Pivot Point With Multiple Forces and Different Directions

In summary, torque on a pivot point is influenced by multiple forces acting in different directions. The total torque is the sum of individual torques produced by each force, calculated as the product of the force magnitude and the distance from the pivot point, taking into account the angle at which the force is applied. When analyzing systems with various forces, it's crucial to consider both the direction and the line of action of each force to determine the net torque and its effect on rotational motion.
  • #1
rosedog09
14
3
Homework Statement
(Questions 7 and 8) Determine the magnitude and net torque acting on the object shown above. (See attached screenshot with figures)
Relevant Equations
T = F*r*sin(angle)

F = force
R= radius
Angle = angle of force
My AP Physics notes state that counterclockwise is generally positive and clockwise is generally negative. This makes sense to me and means forces on opposite sides of the pivot point which act in opposite directions will work together, and this is the logic I applied to answer the problems.

Instead of following this rule, my teacher is saying I should use the direction of the force (i.e two forces acting on opposite sides and in opposite directions of the pivot point will work against each other), but this does not make sense to me as applying and upward force to one side and a downward force to the other will result in a larger net rotation. Could someone explain this to me? Thanks in advance.

P.S Dont take online AP Physics :(

My Work

7.
Net Torque = -100(1) + 50(.5) - 50(.75) = -112.5 Nm

8. Net Torque = -100(.75)(sin30) - 150(.5)(sin30) = -75 Nm
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Teacher Comments
Screenshot_20240422_204437.png

I understand I should probably just trust my teacher, but the online program I am enrolled in has had multiple faulty answer keys and teacher misunderstandings to date, and I would like a more thorough explanation of my error.
 

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  • #2
rosedog09 said:
7.
Net Torque = -100(1) + 50(.5) - 50(.75) = -112.5 Nm
Is the 50N at -.75m acting clockwise or anticlockwise?
rosedog09 said:
8. Net Torque = -100(.75)(sin30) - 150(.5)(sin30) = -75 Nm
Yes.
 
  • #3
7. Ok, I see my mistake, that would make the equation
-100(1)-50(.5)+50(.75) = - 87.5

8. If that is correct, what principle or equation could I show to prove my work to my teacher?
 
  • #4
rosedog09 said:
7. Ok, I see my mistake, that would make the equation
-100(1)-50(.5)+50(.75) = - 87.5

8. If that is correct, what principle or equation could I show to prove my work to my teacher?
The second sentence is wrong. It should read
"F3 is down, so it is negative, and it acts to the right of the pivot, so that is positive, which makes the torque negative."
 
  • #5
haruspex said:
The second sentence is wrong. It should read
"F3 is down, so it is negative, and it acts to the right of the pivot, so that is positive, which makes the torque negative."

Isn't force 3 to the left of the pivot point?

My bigger issue is I don't understand why I am not getting credit for question 8.
 
  • #6
rosedog09 said:
Isn't force 3 to the left of the pivot point?

My bigger issue is I don't understand why I am not getting credit for question 8.
The result is matematically correct as it is the addition of two negative values.
However, we are not sure about the exact statement of your teacher.

Perhaps the location of the signs in the equation?
For the moment induced by F1, the negative sign should be associated to the vertical component of the force (-50 N).
For the moment induced by F2, the negative sign should be associated to the distance (-0.5 m).
 
  • #7
rosedog09 said:
Isn't force 3 to the left of the pivot point?
Sorry, got confused by the two questions being in the wrong order in the "teacher comments ". Let me try again…
Using exactly the same argument in 8 as is used in 7:
F1 is down, so it is negative, and it acts to the right of the pivot, so that is positive, which makes the torque negative;
F2 is up, so it is positive, and it acts to the left of the pivot, so that is negative, which makes the torque negative.
 

FAQ: Torque on a Pivot Point With Multiple Forces and Different Directions

What is torque and how is it calculated?

Torque is a measure of the rotational force applied to an object around a pivot point. It is calculated using the formula: Torque (τ) = Force (F) x Distance (r) x sin(θ), where θ is the angle between the force vector and the lever arm. The distance (r) is the perpendicular distance from the pivot point to the line of action of the force.

How do multiple forces affect the total torque on a pivot point?

When multiple forces act on an object around a pivot point, the total torque is the vector sum of the individual torques produced by each force. Each torque can be calculated separately using the aforementioned torque formula, and the direction of each torque (clockwise or counterclockwise) must be considered to determine the net torque.

What happens if forces are applied in opposite directions?

If forces are applied in opposite directions, they will produce torques that counteract each other. The net torque will be the difference between the torques produced by each force, taking into account their respective distances from the pivot point and their directions. If the torques are equal and opposite, they will cancel each other out, resulting in a net torque of zero.

How does the angle of application of a force affect torque?

The angle at which a force is applied significantly affects the torque produced. The torque is maximized when the force is applied perpendicular to the lever arm (θ = 90 degrees, sin(90°) = 1). As the angle decreases from 90 degrees, the effective component of the force contributing to torque decreases, leading to a reduction in torque.

Can torque be negative, and what does that signify?

Yes, torque can be negative, which typically indicates the direction of rotation. In a standard convention, counterclockwise rotation is considered positive, while clockwise rotation is considered negative. A negative torque value signifies that the net effect of the applied forces tends to rotate the object in a clockwise direction around the pivot point.

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