- #1
firefly.ember
- 1
- 0
Homework Statement
A 75 kg man climbs up a 120 N uniform ladder of length 4 m. The ladder rests on a frictionless wall and a frictionless floor, however the lower end of the ladder is fastened to the wall by a horizontal rope which can withstand a maximum tension of 400 N.
Find
a) The tension in this rope when the man is one third up the ladder.
b) The maximum distance (d) that the man can climb before the rope breaks.
Given:
Fg man: 735 N
Fg ladder: 120 N
l (length) : 4 m
Homework Equations
∑ τorque
∑ Fx
∑ Fy
The Attempt at a Solution
I drew all the forces acting on the ladder and came up with a torque equation but I'm having a hard time dealing with the normal forces and possibly some angles.
∑ τorque = -COS 37 Fg man (d) - COS 37 Fg ladder (l/2) + SIN 53 T (l/3) + SIN 53 n1 (l)
∑ τorque = 586.9 N d -191.7 N + 1.06 T + 3.19 n1 = 0
∑ Fx = -n1 + T = 0
∑ Fy = n2 = Fg man + Fg ladder
Much help with be appreciated. :D
Please provide some detail and way to solve the problem.
Thank you.