- #1
jimkers
- 4
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Hi
So I am busy studying rotational motion and there's an example in the book where they explain that when a car brakes the force of friction acts as a torque force which explains why a car lifts up at the back when braking.
Because the car does no rotational motion they say the net torque is zero and that force N1 counteracts the counterclockwise rotation and the rest count towards the counterclockwise rotation.
Here's my problem, when the calculations are being made, they put in the values for all the forces, multiplied by the distance shown on the figure: 1,5 m and 0,75 m. Shouldn't they account for the angle the force makes with the line between the axis of rotation and the tires (point where the force acts)? I thought only the force acting perpendicular to this line serves in this net force equation.
Thanks in advance.
So I am busy studying rotational motion and there's an example in the book where they explain that when a car brakes the force of friction acts as a torque force which explains why a car lifts up at the back when braking.
Because the car does no rotational motion they say the net torque is zero and that force N1 counteracts the counterclockwise rotation and the rest count towards the counterclockwise rotation.
Here's my problem, when the calculations are being made, they put in the values for all the forces, multiplied by the distance shown on the figure: 1,5 m and 0,75 m. Shouldn't they account for the angle the force makes with the line between the axis of rotation and the tires (point where the force acts)? I thought only the force acting perpendicular to this line serves in this net force equation.
Thanks in advance.