Total potential energy in matrix

In summary, the conversation discusses the matrix A=[3 -1; -1 3] and its properties. It is determined that the quadratic form x'*A*x cannot evaluate to zero for a non-zero vector x, that the equation A*x=b has a unique solution due to the invertibility of A, and that the total potential energy function has a minimum at the unique solution to A*x=b. Further clarification is provided for those unfamiliar with the terminology used.
  • #1
omgitsroy326
30
0
Consider the matrix A=[3 -1; -1 3]. (a) Can the quadratic form x'*A*x evaluate to zero for some non-zero vector x? (x is a 2x1 column vector, and x' means x transposed: usual Matlab notation). (b) Does the equation A*x=b, b arbitrary, have a unique solution? If it does, prove it. (c) Show that the total potential energy f(x)=1/2*x'*A*x-b'*x has a minimum for x that solves the linear equations A*x=b.

This is the question which I'm approached with
my answer is as following
a) No, because it's a symetric matrix only x'Ax = 0 only if vector x = 0.
b) Yes , it is not underdetermined and det does not equal 0
c) iono

i was wondering what you guys thought
 
Last edited:
Physics news on Phys.org
  • #2
a) Compute [itex]x^tAx[/itex] and you will obtain an expression in terms of the entries of x, and this expression, as is given, will be a quadratic form. With this expression, you should easily be able to see that unless x is the zero vector, the expression will not be equal to zero (if x is to have real entries).

b) Compute det(A). Note that it is non-zero. Therefore, A is invertible, so there exists an inverse of A, [itex]A^{-1}[/itex]. If [itex]Ax = b[/itex], then [itex]A^{-1}Ax = A^{-1}b[/itex], so [itex]x = A^{-1}b[/itex], so clearly x exists and is unique.

c) The best way I can think to do this is to compute f(x) to obtain an expression in terms of the entries of x. Essentially, f is a function from [itex]\mathbb{R}^2[/itex] to [itex]\mathbb{R}[/itex]. Compute the Jacobian of f at x, and find the x such that the Jacobian is zero. For all those points, compute the Hessian, and show that there is only one that has a positive definite Hessian. Calculate the value of f at this point. Also, calculate the value of [itex]f(A^{-1}b)[/itex], and show that the two values are the same, thereby showing that the vector where f has it's minimum is indeed the unique solution to [itex]Ax = b[/itex].

If you are unfamiliar with any of the terminology above, you can easily look it up at wikipedia.com or mathworld.com, and then, if you're still stuck, ask for further clarification.
 
  • #3
wow.. thanks.. that was very detailed
 

FAQ: Total potential energy in matrix

What is total potential energy in matrix?

Total potential energy in matrix refers to the sum of the potential energies of all the particles within a given matrix or material. This includes both the potential energy of the interactions between particles, as well as the potential energy associated with the position of each particle within the matrix.

How is total potential energy in matrix calculated?

The calculation of total potential energy in matrix typically involves using mathematical equations to determine the potential energy of each particle and then adding these values together. The specific equations used will depend on the properties of the matrix and the interactions between particles.

Why is total potential energy in matrix important?

Total potential energy in matrix is important because it provides insight into the stability and behavior of a material. A higher potential energy indicates a less stable material, while a lower potential energy indicates a more stable material.

How does temperature affect total potential energy in matrix?

Temperature can affect total potential energy in matrix by altering the movement and interactions of particles within the material. As temperature increases, particles will have more kinetic energy and tend to move more, resulting in changes in potential energy and potentially altering the properties of the material.

How can total potential energy in matrix be manipulated?

Total potential energy in matrix can be manipulated through various means, such as changing the composition or structure of the material, applying external forces or pressures, or altering the temperature. These manipulations can result in changes in potential energy and ultimately affect the behavior and properties of the material.

Similar threads

Replies
1
Views
874
Replies
6
Views
2K
Replies
3
Views
2K
Replies
34
Views
2K
Replies
10
Views
2K
Replies
2
Views
2K
Replies
14
Views
2K
Back
Top