- #1
Cllzzrd
- 7
- 0
Problem:
A dipole consists of charges +q and -q separated by 0.62nm . It is in an electric field 2.6×104 C/N.
What is the work required to rotate the dipole from being oriented parallel to the field to being antiparallel to the field?
Equations:
. 90
w=[tex]\int[/tex](p*E*sin(x)
. 0
t=p*E*sin(x)
Work:
The first part asked for the dipole moment, which i found to be 9.9E-29 C*M
So i calculated the torque to be 2.6E-24 N*M, and the second part was the torque at 45 degrees. I found that this was 1.8E-24 N*M.
The last part asked for the work if it was turned from parallel to the electric field to antiparallel.
so I used the formula above and kept getting 1.47E-24 J. The correct answer was 5.2E-24 and I cannot figure out how to get that answer.
Disclaimer: The only reason I know the correct answer is because I got the wrong answer too many times and so it showed me the right answer. I need to figure out how to do this problem.
A dipole consists of charges +q and -q separated by 0.62nm . It is in an electric field 2.6×104 C/N.
What is the work required to rotate the dipole from being oriented parallel to the field to being antiparallel to the field?
Equations:
. 90
w=[tex]\int[/tex](p*E*sin(x)
. 0
t=p*E*sin(x)
Work:
The first part asked for the dipole moment, which i found to be 9.9E-29 C*M
So i calculated the torque to be 2.6E-24 N*M, and the second part was the torque at 45 degrees. I found that this was 1.8E-24 N*M.
The last part asked for the work if it was turned from parallel to the electric field to antiparallel.
so I used the formula above and kept getting 1.47E-24 J. The correct answer was 5.2E-24 and I cannot figure out how to get that answer.
Disclaimer: The only reason I know the correct answer is because I got the wrong answer too many times and so it showed me the right answer. I need to figure out how to do this problem.