Transform Diff. Eq: Ordinary to More Convenient Expression

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In summary, the conversation discusses the transformation of a differential equation into a more convenient expression for integration. The first equation is given as (1/r)*(dy/dr)*(d2/dr2(r*y))*dr, and the second equation is given as (dy/dx)*(d2y/dx2)*dx = 0.5*(d/dx(dy/dx)^2)*dx. The individual then seeks a simpler expression to integrate, such as d(f(x))/dx, and notes that the independent variables should all be either "x" or "r". They also mention a series solution for ordinary differential equations and ask about the analyticity of x and x^2. The expert responds by clarifying that x and
  • #1
tbk1
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I wish to transform my diff. eq.
(1/r)*(dy/dr)*(d2/dr2(r*y))*dr into a more convenient expression, in a similar to the following transformation:

(dy/dx)*(d2y/dx2)*dx = 0.5*(d/dx(dy/dx)^2)*dx
which is a very convenient expression for integration ==> 0.5* (dy/dx)^2

So far, I have found the following expression, to which I haven't found the integration answer.
(1/(2*x^4)*(d/dx(x^2*dy/dx)^2)

I would appreciate your help
tbk1
 
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  • #2
If you want to solve something, you need an equation. I do not see any "=" in your problem.
Your first expression has an additional dr which I would not expect there.

Converted to LaTeX, as it is easier to read:
$$\frac{1}{r} \left(\frac{dy}{dr}\right) \left(\frac{d^2}{dr^2} (ry)\right) dr$$
$$\frac{1}{2x^4}\frac{d}{dx} \left(x^2 \frac{dy}{dx}\right)^2$$
 
  • #3
Thank you for your quick reply. I do not LaTex, so till I'll find a quick way to translate it, I wish to make the following remarks:
1. You're right, a differential, dr, is missing of course.
2. You may address it as an homogeneous equation, but the truth is that I simply seek the simpler expression to integrate, something like d(f(x))dx, so that the integral result will be
3. I mixed "x" and "r", all the independent variables should be either "x" or "r".
Thanks again
tbk1
 
  • #4
The second equation looks good in that respect. Multiply with x^4, and you can integrate both sides. The left side is trivial (as it is df(x)/dx), the right side is 0 or something you can integrate, and afterwards you can try to simplify the result to integrate again.
 
  • #5
oops, reading your reply, I understand that one cannot address the equation as a homogeneous one, but rather as equal to a constant, than the term "x^4" cannot be eliminated.
 
  • #6
tbk1 said:
I wish to transform my diff. eq.
(1/r)*(dy/dr)*(d2/dr2(r*y))*dr into a more convenient expression, in a similar to the following transformation:

(dy/dx)*(d2y/dx2)*dx = 0.5*(d/dx(dy/dx)^2)*dx
which is a very convenient expression for integration ==> 0.5* (dy/dx)^2

So far, I have found the following expression, to which I haven't found the integration answer.
(1/(2*x^4)*(d/dx(x^2*dy/dx)^2)

I would appreciate your help
tbk1

Hi !
Fishy wording ! I cannot understand exactly what is the equation.
Would you mind rewrite only the first equation, without explanation nor comment which could confused us. Only one equation on the patern :
(1/r)*(dy/dr)*(d2/dr2(r*y)) = what ?
 
  • #7
tbk1 said:
oops, reading your reply, I understand that one cannot address the equation as a homogeneous one, but rather as equal to a constant, than the term "x^4" cannot be eliminated.
It cannot be eliminated, but it is easy to integrate it with respect to x.
 
  • #8
Hi,
I have a question regarding to the series solution of ordinary differential equation . my question is , I've found that if we have to solve y"+p(x)y'+q(x)y=0 by power series method, we have to find a point say "a" where p(x) & q(x) become analytic , and by the definition of analytic function a function will be analytic if it has a taylor series expansion around a given neighbourhood point and for taylor series expansion the function must be infinitely differentiable but for the equation y"+xy'+x^2y=0. how x & x^2 become analytic as by the 2 differentiation of x and 3 differentiation of x^2 it becomes zero , and so there not infinitely differentiable ?
Thanx in advance
 
  • #9
Shan K said:
how x & x^2 become analytic as by the 2 differentiation of x and 3 differentiation of x^2 it becomes zero , and so there not infinitely differentiable ?
The first derivative of x² is 2x
The second derivative is 2
The third derivative is 0 because the derivative of any constant function is 0.
The fourth derivative is 0 because the derivative of any constant function is 0.
And so on. All successive derivatives are 0.
So, x² is infinitely differentiable.
 
  • #10
JJacquelin said:
The first derivative of x² is 2x
The second derivative is 2
The third derivative is 0 because the derivative of any constant function is 0.
The fourth derivative is 0 because the derivative of any constant function is 0.
And so on. All successive derivatives are 0.
So, x² is infinitely differentiable.

Thanx
 

FAQ: Transform Diff. Eq: Ordinary to More Convenient Expression

What is the purpose of transforming a differential equation into a more convenient expression?

The purpose of transforming a differential equation into a more convenient expression is to simplify the equation and make it easier to solve. It can also help to uncover hidden patterns or relationships within the equation.

What are some common methods for transforming differential equations?

Some common methods for transforming differential equations include substitution, change of variables, and integrating factors. These methods can help to simplify the equation and make it easier to solve.

When should one consider transforming a differential equation into a more convenient expression?

One should consider transforming a differential equation into a more convenient expression when the original equation is difficult to solve or contains complex terms. Transforming the equation can make it easier to understand and solve.

How does transforming a differential equation affect the solutions?

Transforming a differential equation does not change the solutions, but it can change the form of the solutions. The transformed equation may have simpler, more general, or more intuitive solutions.

Are there any drawbacks to transforming a differential equation?

One potential drawback of transforming a differential equation is that it may introduce additional unknown variables or parameters. This can make the equation more complex and potentially more difficult to solve. It is important to carefully consider the trade-offs before deciding to transform a differential equation.

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