Transform PDE Problem Solutions with Fourier Transforms | Get Help Now

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In summary, the problem involves solving a fourth-order differential equation using Fourier transforms. The equation is d4u + K2*d2u = 0, and the initial conditions are u(x,0)= f(t) and u'(x,0)= g(t). The goal is to find the solution in terms of f(t) and g(t) with the given boundary conditions u''(L,t)= 0 and u'''(L,t)= 0.
  • #1
mike1111
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Homework Statement


Use Fourier transforms to get solution in terms of f(t) adn g(t)

Homework Equations


d4u + K2*d2u =0
dx4 (space) dt2

u(0,t)=f(t)
u'(0,t)=g(t)
u''(L,t)=0
u'''(L,t)=0

The Attempt at a Solution


I been working no it for hours the best I got is
k4U +K* (d2U/dt2) =0
I'm not sure where to go since i don't hve initial conditions

Really need someone to show me how to do the question or a similar one
 
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  • #2
mike1111 said:

Homework Statement


Use Fourier transforms to get solution in terms of f(t) adn g(t)


Homework Equations


d4u + K2*d2u =0
dx4 (space) dt2

u(x,0)=f(t)
u'(x,0)=g(t)
u''(L,t)=0
u'''(L,t)=0

The Attempt at a Solution


I been working no it for hours the best I got is
k4U +K* (d2U/dt2) =0
I'm not sure where to go since i don't hve initial conditions
Yes, you do have initial conditions! They are u(x,0)= f(t) and u'(x,0)= g(t). (I assume the ' denotes differentiation with respect to t.)

Really need someone to show me how to do the question or a similar one
 
  • #3
my fault, there aren't meant to be initial ocnidtion, just fixed the question
 

FAQ: Transform PDE Problem Solutions with Fourier Transforms | Get Help Now

What is a Fourier transform and how does it relate to solving PDEs?

A Fourier transform is a mathematical tool used to decompose a function into its frequency components. In the context of solving PDEs, it allows us to transform a differential equation in the spatial domain into an algebraic equation in the frequency domain, making it easier to solve.

Can any PDE problem be solved using Fourier transforms?

No, not all PDE problems can be solved using Fourier transforms. The PDE must have certain properties, such as linearity and homogeneity, in order for the Fourier transform method to be applicable.

How does transforming a PDE problem with Fourier transforms make it easier to solve?

Transforming a PDE problem with Fourier transforms allows us to convert the problem from a differential equation in the spatial domain to an algebraic equation in the frequency domain. This often simplifies the problem and makes it easier to solve using standard algebraic techniques.

What are some common applications of using Fourier transforms to solve PDE problems?

Fourier transforms are commonly used in applications such as signal processing, image analysis, and solving PDE problems in physics and engineering. They are also used in mathematics to study the properties of functions and to prove theorems.

Are there any limitations or drawbacks to using Fourier transforms for PDE problem solutions?

One limitation of using Fourier transforms for PDE problem solutions is that the problem must have certain properties, such as linearity and homogeneity, for the method to be applicable. Additionally, the Fourier transform method may not work for all types of boundary conditions, and it may not always yield an explicit solution.

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