- #1
thoradicus
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http://www.xtremepapers.com/papers/CIE/Cambridge%20International%20A%20and%20AS%20Level/Physics%20%289702%29/9702_s05_qp_4.pdf
6b
flux linkage = BA
B=F/iL
from my understanding, if B=F/iL , if the current is zero, shouldn't B be infinite,hence phi infinite or something? As seen in the 1st graph. Why does the graph follow a sine graph instead of phi(max)sin(wt)?
Also, can anyone explain why the phase difference is 90 deg instead of 180? i thought the EMF curve would just follow a cos curve because of the negative sign of faraday's law, hence 180 phase difference.
Homework Statement
6b
Homework Equations
flux linkage = BA
B=F/iL
The Attempt at a Solution
from my understanding, if B=F/iL , if the current is zero, shouldn't B be infinite,hence phi infinite or something? As seen in the 1st graph. Why does the graph follow a sine graph instead of phi(max)sin(wt)?
Also, can anyone explain why the phase difference is 90 deg instead of 180? i thought the EMF curve would just follow a cos curve because of the negative sign of faraday's law, hence 180 phase difference.