- #1
AN630078
- 242
- 25
- Homework Statement
- Hello, hypothetically if I wanted to create a transformer which had an output voltage is ten times the input voltage, how would I do this?
- Relevant Equations
- Vs=-Ns (dΦ)/(dt)
Vp/Vs=Np/Ns
I understand that transformers function using electromagnetic induction and Faraday's Law.
This implies; Vs=-Ns (dΦ)/(dt)
Meaning the secondary voltage is proportional to the number of turns on the secondary coil.
Vs∝Ns
Using the relationship; Vp/Vs=Np/Ns
If we want Vs=10Vp that would imply that we require a 10:1 turns ratio, i.e. ten times as many turns on the primary coil than the the secondary?
10Vp=10/1*Vs
So to increase the output voltage to ten times that of the input voltage would we just increase the number of turns on the secondary coil by 1/10 of that on the primary; so Ns=1?
Or if Vs and Ns are directly proportional then we would increase the number of by multiplying by 10?
This implies; Vs=-Ns (dΦ)/(dt)
Meaning the secondary voltage is proportional to the number of turns on the secondary coil.
Vs∝Ns
Using the relationship; Vp/Vs=Np/Ns
If we want Vs=10Vp that would imply that we require a 10:1 turns ratio, i.e. ten times as many turns on the primary coil than the the secondary?
10Vp=10/1*Vs
So to increase the output voltage to ten times that of the input voltage would we just increase the number of turns on the secondary coil by 1/10 of that on the primary; so Ns=1?
Or if Vs and Ns are directly proportional then we would increase the number of by multiplying by 10?