Transition Radiation rates of Hamiltonian

In summary, the expression by taking expectation value in kth state is significant. Radiative transition rates play a role in the oscillator strength.
  • #1
unscientific
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Homework Statement



29p2edt.png


Part (a): Show the Commutation relation [x, [H,x] ]
Part (b): Show the expression by taking expectation value in kth state.
Part (c): Show sum of oscillator strength is 1. What's the significance of radiative transition rates?

Homework Equations


The Attempt at a Solution



Part (a)

Manged to show.

Part (b)

[tex]\langle H \rangle = \langle k|\frac{p^2}{2m} + V|k\rangle[/tex]
[tex]\frac{1}{2m}\langle k|p^2|k\rangle + \langle k|V|k\rangle[/tex]

Not sure what to do at this point - it looks nothing like the answer.
 
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  • #2
Instead of taking the expectation value of equation (2.2), take the expectation value of the commutation relation that you showed in part (a).
 
  • #3
TSny said:
Instead of taking the expectation value of equation (2.2), take the expectation value of the commutation relation that you showed in part (a).

I tried and that leads to nowhere..

[tex]\langle \left[x,[H,x]\right] \rangle[/tex]
[tex]= \langle k|\left[ x, [H,x] \right] |k\rangle[/tex]
[tex] = \langle k | [x,Hx] - [x,xH]|k\rangle[/tex]
 
Last edited:
  • #4
unscientific said:
I tried and that leads to nowhere..

[tex] = \langle k | [x,Hx] - [x,xH]|k\rangle[/tex]

Keep going. Write out [x,Hx] and [x,xH]. Then judiciously insert the identity operator in the form ##1 = \sum_n |n\rangle \langle n| ##
 
  • #5
TSny said:
Keep going. Write out [x,Hx] and [x,xH]. Then judiciously insert the identity operator in the form ##1 = \sum_n |n\rangle \langle n| ##

[tex]= \langle k | [x,Hx] - [x,xH]|k\rangle[/tex]
[tex] = \langle k | [x,H]x - x[x,H] |k\rangle[/tex]
[tex] = \langle k | xHx - Hx^2 -x^2H + xHx|k\rangle[/tex]
 
  • #6
unscientific said:
[tex]= \langle k | [x,Hx] - [x,xH]|k\rangle[/tex]
[tex] = \langle k | [x,H]x - x[x,H] |k\rangle[/tex]
[tex] = \langle k | xHx - Hx^2 -x^2H + xHx|k\rangle[/tex]

Take ##\langle k | xHx |k\rangle## and insert the identity: ##\langle k | x H \hat{1} x |k\rangle##
 
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  • #7
TSny said:
Take ##\langle k | xHx |k\rangle## and insert the identity: ##\langle k | x H \hat{1} x |k\rangle##
Yeah got it!
 

Related to Transition Radiation rates of Hamiltonian

1. What is transition radiation and how is it related to Hamiltonian?

Transition radiation is a phenomenon that occurs when a charged particle transitions from one medium to another. The resulting radiation is caused by the change in the particle's energy and is related to Hamiltonian because it involves the transfer of energy between the particle and the medium.

2. How does Hamiltonian affect the rate of transition radiation?

Hamiltonian is a mathematical operator that describes the total energy of a system, including the kinetic and potential energies of the particles. The rate of transition radiation is directly proportional to the energy of the particle, so the Hamiltonian plays a crucial role in determining the rate of transition radiation.

3. Are there any factors besides Hamiltonian that can affect transition radiation rates?

Yes, there are several factors that can influence the rate of transition radiation, including the charge and velocity of the particle, the properties of the medium, and the angle of incidence of the particle on the medium.

4. How is the Hamiltonian used in calculating transition radiation rates?

The Hamiltonian is used to calculate the energy of the particle before and after the transition to determine the amount of energy that is transferred to the medium in the form of radiation. This calculation can be done using the principles of quantum mechanics and electromagnetic theory.

5. What is the significance of understanding transition radiation rates in Hamiltonian?

Understanding the relationship between transition radiation and Hamiltonian is important for various applications, such as particle accelerators and medical imaging. It also helps in studying the behavior of charged particles in different mediums and gaining insights into the fundamental principles of quantum mechanics and electromagnetism.

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