Translation-invariant systems and binary functions of spatial variables

  • #1
hokhani
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TL;DR Summary
the correctness of the relation f(r,r')=f(r-r') in translation-invariant systems
My question is about a statement in the book, Many-Body Quantum Theory in Condensed Matter Physics: An Introduction, by Henrik Bruus, Karsten Flensberg in appendix A:
In a translation invariant system, any physical observable ##f(\vec r,\vec r')## of two spatial variables ##\vec r## and ##\vec r'## can only depend on the difference between the coordinates and not on the absolute position of any of them, $$f(\vec r,\vec r')=f(\vec r - \vec r').$$ However, I think in one unit cell if we shift identically both ##\vec r## and ##\vec r'## then this statement does not seem necessarily correct!
 
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  • #2
hokhani said:
I think in one unit cell if we shift identically both ##\vec r## and ##\vec r'## then this statement does not seem necessarily correct!
What do you mean with that ? The statement doesn't mention unit cells.
And what is 'shift identically' ?

##\ ##
 
  • #3
hokhani said:
TL;DR Summary: the correctness of the relation f(r,r')=f(r-r') in translation-invariant systems

coordinates and not on the absolute position of any of them, f(r→,r→′)=f(r→−r→′). However, I think in one unit cell if we shift identically both r→ and r→′ then this statement does not seem
For any position vector R
[tex]f(\mathbf{r}, \mathbf{r'})=f(\mathbf{r}+\mathbf{R}, \mathbf{r'}+\mathbf{R})[/tex]
choosing R=-r or R=-r'
[tex]=f(\mathbf{r}-\mathbf{r'},0))=f(0, \mathbf{r'}-\mathbf{r}):=F(\mathbf{r}-\mathbf{r'})[/tex]
 

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