- #1
jmm5872
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A transverse wave in a wire with a linear density 2.35 g/m has the form y(x,t) = (1.4 cm)sin[(5.45 m-1)x−(6950 s-1)t].
What is the tension?
I took the A=.014m, k=5.45 /m, and [tex]\omega[/tex]=6950.
I used the formula for the max velocity = A[tex]\omega[/tex]
v=(.014)(6950)=97.3
Then I used the formula for the speed of a wave on a string v=[tex]\sqrt{\frac{F}{M/L}}[/tex].
97.3=[tex]\sqrt{\frac{F}{.00235}}[/tex]
And I got F=22.24813
This was not the correct answer. I would appreciate any advice.
I attempted to find the velocity of the pulse : (0.943s)(3.29m)(8)=24.81976
What is the tension?
I took the A=.014m, k=5.45 /m, and [tex]\omega[/tex]=6950.
I used the formula for the max velocity = A[tex]\omega[/tex]
v=(.014)(6950)=97.3
Then I used the formula for the speed of a wave on a string v=[tex]\sqrt{\frac{F}{M/L}}[/tex].
97.3=[tex]\sqrt{\frac{F}{.00235}}[/tex]
And I got F=22.24813
This was not the correct answer. I would appreciate any advice.
I attempted to find the velocity of the pulse : (0.943s)(3.29m)(8)=24.81976