Trapezoidal Rule: Find T8 & M8 for ∫cos(x^2)dx from 1 to 0

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To find the approximations T8 and M8 for the integral of cos(x^2) from 1 to 0, n is indeed equal to 8. The trapezoidal rule requires the formula T[n] = (b-a)/(2n) * (f(a) + 2 * Σf(xi) + f(b)), where you evaluate the function at specified intervals. The user suggests using f(0), f(0.2), f(0.4), f(0.6), f(0.8), and f(1) for their calculations. It is also mentioned to use the degree mode on the calculator for accurate results. Proper setup and calculations will yield the desired approximations.
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hey guys... i kinda forgot how to do this

question is: find the approximations T8 and M8 for integral of cos(x^2)dx from 1 to 0

now my question is whether or not that 8 means that n=8

and also, is this right?

id do the following:

n/2[f(0)+f(.2)+f(.4)+f(.6)+f(.8)+f(1)]

and id use the degree mode on my calculator

is that how i set it up?
 
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arg can someone help me? please
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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