- #1
Kat007
- 29
- 0
Hello,
Could you please clarify if this is correct:
If tan^(-1)(x) = Pi/2 - tan^(-1)(1/x)
Then if we have (ax) as the angle where a is a constant, do we get:
tan^(-1)(ax) = Pi/2 - tan^(-1)(a/x)
or does the constant go on the bottom with the x? i.e. or:
tan^(-1)(ax) = Pi/2 - tan^(-1)(1/(ax))
Thank you very much,
Kat
Could you please clarify if this is correct:
If tan^(-1)(x) = Pi/2 - tan^(-1)(1/x)
Then if we have (ax) as the angle where a is a constant, do we get:
tan^(-1)(ax) = Pi/2 - tan^(-1)(a/x)
or does the constant go on the bottom with the x? i.e. or:
tan^(-1)(ax) = Pi/2 - tan^(-1)(1/(ax))
Thank you very much,
Kat