- #1
Tseliottt
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Homework Statement
Find limits of integration for volume of upside down cone with vertex on origin and base at z=1/sqrt(2). Angle at vertex is pi/2. Do this in cylindrical coordinates.
Homework Equations
None.
The Attempt at a Solution
My inner integral conflicts with the books solution. So in my triple integral, the outsides are right: 0<theta<2pi ; 0<r<1/sqrt(2)
But my inner integral is r<z<1/sqrt(2) and the book says its r<z<1.
Where does this 1 come from? I thought the max height was 1/sqrt(2)?
Sorry if my formats messed up. Typing this on my phone.