- #1
Locoism
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- 0
Homework Statement
Find the volume of the solid that lies between
z=x2+y2 and
x2+y2+z2=2
Homework Equations
z=r2
z=√(2-r2)
The Attempt at a Solution
So changing this into cylindrical coordinates, I get
z goes from r2 to √(2-r2)
r goes from 0 to √2
theta goes from 0 to 2π
so we get [itex] \int_0^{2π} \int_0^{\sqrt{2}} \int_{r^2}^{\sqrt{2-r^2}} r dzdrdt[/itex]
I dunno... something feels off about this. I think this way it would take into account the negative area on the outside of the curve... How else could I set up the integral?