- #1
jackscholar
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Homework Statement
I have a graph 1/x^2=y^2+z^2 where z=rsin(θ) and y=rcos(θ)
where 0≤r≤1 and 0≤θ≤2∏ on the zy-plane
The end result is attached (sorry, I'm not aware of how to use Latex :[ )
I can kind of understand how they determined the first bounds for the integral: the lowest x co-ordinate is 0 and the maximum co-ordinate is always 1/r. I can also kind of understand how they determined the second integral bounds, the maximum possible value for r is 1 and the lowest possible value for r is 0. For the angle the largest possible angle is 2∏ whereas the lowest possible angle is 0. I do not, however, understand why there is a half in front of the triple integral.