MHB Trouble determining truth value of logic statements

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The discussion focuses on evaluating the truth values of two logical statements under specific assumptions about the variables a, b, c, and d. The first statement, not(a V b) -> s, is confirmed to be correct, while the second statement involves the unknown variable r, complicating its evaluation. It is noted that if r is true, the statement becomes false, but if r is false, the statement is true. The equivalence of the second statement to ¬r under the given assumptions indicates that it lacks a definite truth value. Overall, the complexity arises from the uncertainty surrounding the value of r.
chelseajjc95
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For the folowing two problems determine the truth value of each statement:
assume a and b are true and c and d are false.

not(a V b) -> s
not( T V T) -> s
F -> s
T

r -> [(d -> w) <-> (a ^ c )]
r -> [(F -> w) <-> ( T ^ F)]
r -> [T <-> F]
r -> F

I am fairly certain I did the first one correct but I would like some confirmation. The second one I am unsure how to evaluate
because the value of r is unknown and if r is t then the statement will be false but if r is false then the statement will be true.
 
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You are right: $r\to [(d\to w) \leftrightarrow (a\land c )]$ is equivalent to $\neg r$ under the assumptions about $a$, $b$, $c$ and $d$, so the original formula does not have a definite truth value.
 
I was reading a Bachelor thesis on Peano Arithmetic (PA). PA has the following axioms (not including the induction schema): $$\begin{align} & (A1) ~~~~ \forall x \neg (x + 1 = 0) \nonumber \\ & (A2) ~~~~ \forall xy (x + 1 =y + 1 \to x = y) \nonumber \\ & (A3) ~~~~ \forall x (x + 0 = x) \nonumber \\ & (A4) ~~~~ \forall xy (x + (y +1) = (x + y ) + 1) \nonumber \\ & (A5) ~~~~ \forall x (x \cdot 0 = 0) \nonumber \\ & (A6) ~~~~ \forall xy (x \cdot (y + 1) = (x \cdot y) + x) \nonumber...
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