- #1
sony
- 104
- 0
Ok, so I have the integral of (x^2 + 1) / (x^3 + 8) dx
I use partial fractions and end up with two integrals, the one I cannot solve is:
1/12 * "integral of" (7x-4) / [(x-1)^2 +3 ] dx
With u=x-1 I get
(7u-3) / (u^2+3) du
But I have no Idea of how to solve it, the answer in the books shows the step up to this, but jumps over what to do with the last part and writes the answer (something involving tan^-1 and ln)
Please help!
Thanks
I use partial fractions and end up with two integrals, the one I cannot solve is:
1/12 * "integral of" (7x-4) / [(x-1)^2 +3 ] dx
With u=x-1 I get
(7u-3) / (u^2+3) du
But I have no Idea of how to solve it, the answer in the books shows the step up to this, but jumps over what to do with the last part and writes the answer (something involving tan^-1 and ln)
Please help!
Thanks