- #1
rgalvan2
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Homework Statement
An electron of energy E = 2.10 eV is incident on a barrier of width L = 0.67 nm and height Vo = 3.10 eV
What is the probability that the electron will pass through the barrier?
Homework Equations
I know that T=Ge^-2KL.
K=2pi*sqrt((E-Uo)/1.505eVnm^2))
G=16*(E/Uo)*(1-(E/Uo))
The Attempt at a Solution
K=5.12nm^-1
G=3.5
T=3.5*exp(-2*(5.12nm^-1)*(.67nm))
nm cancels in the exponent so:
T=3.5*exp(-2*5.12*.67)=3.5*.001=.35%
This isn't the right answer though. I've tried 3.5,
35, .035, and .0035 and none of these answers are right. Any help? Thanks!