- #1
Galloleo
- TL;DR Summary
- I have a question about this classic problem based on information I read in another post.
Two 95 W (120V) light bulbs are wired in series, then the combination is connected to a 120 V supply.
How much power is dissipated by each bulb?
Answer 24W
I followed the explanations as such:
r1 = 120^2/(95) = 151.8
R = 303
r2 = r1
W = 190
I = P/V
I = 190/120 = 1.58
v1 = 190/1.58 = 60
p1 = 60^2/(151.8) = 23.7w
p2 = p1
I = E/R as well.
My question is about this:
I = 120/303 = 0.396 which is about 1/4th the amps originally calculated.
What have I failed to consider? There is something about this relationship I don't understand.
How much power is dissipated by each bulb?
Answer 24W
I followed the explanations as such:
r1 = 120^2/(95) = 151.8
R = 303
r2 = r1
W = 190
I = P/V
I = 190/120 = 1.58
v1 = 190/1.58 = 60
p1 = 60^2/(151.8) = 23.7w
p2 = p1
I = E/R as well.
My question is about this:
I = 120/303 = 0.396 which is about 1/4th the amps originally calculated.
What have I failed to consider? There is something about this relationship I don't understand.