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Rohaaan
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Homework Statement
Two masses, m1 = 1.65kg and m2 = 3.30kg, attached by a massless rod parallel to the inclined plane on which they both slide, travel along the plane with m1 trailing m2. The angle of incline is 30°. The coefficient of kinetic friction between m1 and the incline is μ1 = 0.226; that between m2 and the incline is μ2 = 0.113.
What is the tension in the rod?
Homework Equations
Ff = μk × FN
FN = mgcosθ
The Attempt at a Solution
So, for m1:
Ff1 = μ1 × FN
Ff1 = 0.226 × mgcos30
Ff1 = 0.226 × 14.29
Ff1 = 3.23N
Force Down Incline = mgsin30
Force Down Incline = 8.25N
Therefore, Tension 1 = Force Down Incline - Ff1 = 5.02N
And for m2:
Ff1 = μ1 × FN
Ff1 = 0.113 × mgcos30
Ff1 = 0.226 × 28.58
Ff1 = 3.23N
Force Down Incline = mgsin30
Force Down Incline = 16.5N
Therefore, Tension 2 = Force Down Incline - Ff2 = 13.27NFinally, Total Tension = Tension 2 - Tension 1 = 8.25N
There are no answers for this question, so I came on here hoping that someone may be able to correct me if I have done something wrong, or possibly verify my answer.
Any help greatly appreciated!
Thanks :)