Two masses connected by spring, find period of oscillation

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To find the period of oscillation for two masses connected by a spring, the equations of motion for each mass need to be established based on their positions and the spring's equilibrium length. The forces acting on the masses can be expressed as m1(x1)'' = -k(x1 - x2 + L) and m2(x2)'' = -k(x2 - x1 - L). A suggestion is made to simplify the problem by using the concept of reduced mass, which allows the two-body problem to be treated as a one-body problem. It is noted that the oscillation period can be derived without complex differential equations, focusing instead on the effective spring constants. Understanding these principles will lead to the correct calculation of the oscillation period.
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Homework Statement



Two masses are connected by spring and slide freely without friction along horizontal track. What is period of oscillation?

Homework Equations


The Attempt at a Solution



My solution:
let x1 be position of mass 1 (m1) and x2 be position of mass 2 (m2) and L be length of spring in equilibrium.
Then, the total stretch of the spring is x2-x1-L. Also, F1 = -F2. Thus:

m1(x1)'' = -k(x1 - x2 + L)
m2(x2)'' = -k(x2 - x1 - L)

Solving for x2 from first eqn and substituting back into second eqn yield:

\frac{d^2}{dt^2}[\frac{m1 m2}{k}(x1)''+(m1+m2)x1] = 0

I am unsure how to proceed from here, any hints? I would like to just multiply both sides by (dt^2)/d^2 but I am unsure if this is mathematically correct? It does simplify the problem though and gives me right answer...
 
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You should be well aware that ##\frac{d^2}{dt^2}## isn't a fraction.
 
I don't think you really need differential equations for this one, since there is no external force there is a point on the spring that neither stretches nor compresses. on either side of this point is 2 springs with different spring constants, so effectively you have two different oscillators, with the same period.
 
Do you know about reduced mass and how to convert a two-body problem into a one-body problem?
 

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