Two particles in superposition

In summary, the conversation discusses the interaction and collapse of wave functions in an isolated system consisting of two particles in superposition. The possibility of interaction between the particles depends on the type of particle and the presence of a coupling mechanism. The term "collapse" is debated, as it may refer to a mixing of product states or a memory of past interactions. The topic also delves into the idea of isolating a system and the potential effects of external forces, such as gravity, on the collapse of the wave function.
  • #1
freerangequark
17
0
If you had an isolated system consisting of two particles both of which were in superposition, would they interact with each other and collapse each other's wave function?

Thanks,
FRQ
 
Physics news on Phys.org
  • #2
Whether or not they would interact depends on what kind of partcle it is. There needs to be some sort of "coupling mechanism" , e.g. some electromagnetic dipole-dipole interaction. If there is a "classical" interaction there will also be a "QM" interaction.

The word "collapse" is somewhat missleading. Wha happens if you have e.g. two coupled spin 1/2 systems is essentially that a "hybrid" system is created with new energy levels, wavefunctions etc. However, it is still very much a QM system.
 
  • #3
Not being anything more than a reader of popular physics books, I'm trying to understand what you're saying.

Are you talking about an entangled pair?

In my example, I was wondering what would happen if the isolated system contained two of the same type of particle... let's say a pair of non-entangled photons in superposition. (when I say non-entangled, I mean not entangled with each other.)

Thanks,
FRQ
 
  • #4
freerangequark said:
In my example, I was wondering what would happen if the isolated system contained two of the same type of particle... let's say a pair of non-entangled photons in superposition. (when I say non-entangled, I mean not entangled with each other.)

One could also consider the two electrons in a helium atom (assuming that the core is approximately fixed due to its large mass). Without interaction the electrons would remain in a product state (in an antisymmetrized form, to be precise) for all time if they were initially. A product state is a state where the measurement of position of electron 1 yields independent results of the measurement of position of electron 2:

[tex]\psi(x_1,x_2) = \psi_1(x_1)\cdot\psi_2(x_2)[/tex]

(for simplicity I've neglected fermionic antisymmetrization)

But if the electrons do interact, an initial product state will get mixed with other product states during the time evolution. Therefore the measurement of electron 2 will almost always depend on measurement of electron 1:

[tex]\psi(x_1,x_2) \not= \psi_1(x_1)\cdot\psi_2(x_2)[/tex]

Of course even a system without interaction need not always be in a product state. For example, it may have started as a product state in the past (e.g. after you have simultaneously measured the position of both electrons), then you "turned" the interaction on, which has mixed product states, then you turn the interaction off. The system will then remain in its current mixed state, although there is no interaction any more. Thus the superposition of pure product states can be considered as a kind of memory of past interactions.
 
Last edited:
  • #5
freerangequark said:
In my example, I was wondering what would happen if the isolated system contained two of the same type of particle... let's say a pair of non-entangled photons in superposition. (when I say non-entangled, I mean not entangled with each other.)

The problem is that something "external" to the system might be able to collapse the wavefunction of said system, but something "internal" can not. So for example, if you had one photon, another photon can come along and potentially "collapse" the wavefunction. HOWEVER: the system of two photons has a wavefunction that has not collapsed. Another photon can come along and collapse the wavefunction of the 2-photon system, but the wavefunction of the 3-photon system remains uncollapsed. This chain can go on forever!

This is a problem that lives in the heart of the physics subfield known as "Quantum Cosmology", where people have tried to construct the "wavefunction of the universe" (Wheeler-DeWitt Equation). What is not clear is that even if such a thing exists (and I'm not saying that it does or doesn't) - can it ever be "collapsed"?

Another problem that has been popularized by Roger Penrose is: how can you ever isolate a system, since gravity couples to everything? Therefore, isn't the (**incredibly** tiny!) gravitational pull from the Andromeda galaxy "collapsing the wavefunction" of every isolated system we construct?

As you can see, FRQ, this is a very deep problem!
 
  • #6
What happens if two particles (such that the state of each one individually could be expressed as a superposition of basis states, but which aren't initially entangled) interact? Don't they just become entangled (such that the state of the pair is not yet "collapsed" but could be expressed as a superposition...)?

blechman said:
Another problem that has been popularized by Roger Penrose is: how can you ever isolate a system, since gravity couples to everything? Therefore, isn't the (**incredibly** tiny!) gravitational pull from the Andromeda galaxy "collapsing the wavefunction" of every isolated system we construct?

Wouldn't that only be true if the interaction were strong enough that you could determine something about the "isolated system" by measuring changes over in Andromeda? (Lately, Penrose has been known to publicise some questionable ideas.)
 
  • #7
cesiumfrog said:
Wouldn't that only be true if the interaction were strong enough that you could determine something about the "isolated system" by measuring changes over in Andromeda? (Lately, Penrose has been known to publicise some questionable ideas.)

Perhaps. I'm not saying I necessarily agree with it. I only throw it out there as a possible added confusion. Penrose has said some outlandish things in his time, but he's a very smart guy! I think it's still an open debate as to how serious to take such issues. I am not a QC expert, and every time I try to get into it, I come out with a splitting headache! :rolleyes:
 

FAQ: Two particles in superposition

What is superposition in the context of particles?

Superposition refers to the quantum mechanical phenomenon where a particle exists in multiple states simultaneously, rather than in a single definite state. This means that the particle can be in multiple places or have multiple properties at the same time.

How are particles put into superposition?

Particles can be put into superposition through a process of quantum interference, where two or more states of the particle are combined, resulting in a new state that is a combination of the original states.

What is the significance of superposition in quantum mechanics?

Superposition is one of the key principles of quantum mechanics that allows for the explanation of many phenomena, such as the wave-like behavior of particles and the concept of entanglement. It also forms the basis for technologies such as quantum computing.

How is superposition observed in experiments?

In experiments, superposition is observed through the interference patterns that particles exhibit when they are in a state of superposition. This can be seen in the famous double-slit experiment, where particles behave as both waves and particles when in superposition.

Can superposition be observed in everyday life?

No, superposition is a phenomenon that is only observed at the quantum level and cannot be observed in everyday life. The principles of quantum mechanics only apply to very small particles, such as atoms and subatomic particles, and do not have any noticeable effects on larger objects.

Similar threads

Replies
2
Views
2K
Replies
1
Views
1K
Replies
7
Views
1K
Replies
2
Views
2K
Replies
25
Views
2K
Replies
4
Views
1K
Back
Top