Two questions regarding linear momentum and conservation

In summary: So, I would better answer it here.As you know that I am a newbie, I am not very well known to all the features of this forum. I still cannot interpret a user's status (Admin, Mod, etc.). I saw that the thread was closed, but there was no mention of any moderator. So, I asked you.And one more thing, you said : "You are supposed to report it using the red exclamation mark". I could not follow that. Did you mean the report button ?In summary, the conversation involves two questions (63 and 64) regarding linear momentum and conservation of momentum. In problem 63, the equations for conservation of kinetic energy and conservation of momentum along the x and y axes are
  • #1
sankalpmittal
785
26
Two questions regarding linear momentum and conservation...

Homework Statement



See : http://postimg.org/image/e7vvycs5t/

Questions : 63 and 64

Sorry, the image is little blurred. I was in so hurry that I could not take a better snap shot. Please do not left click on the image. (You know to what extent the blurring can enhance.)

Homework Equations



Conservation of law of conservation of linear momentum, and collision equations.

The Attempt at a Solution



For first :

For body 1 : v1 = 0

For body 2 :

v2 = u1

"v[index]" is final velocity of body 1 or 2.
u1 is initial velocity of body 1.

Ok, so how does this imply that bodies go right angle at each other ?

For second :

I seriously do not know how to begin. I am sorry. Is there some sort of geometry ? I cannot follow the hint given in the book.

Please hep !

Thanks in advance... :smile:
 
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  • #2
For problem 63, apply the equations for conservation of kinetic energy and conservation of momentum along the x and y axes. By a few steps of mathematical juggling you should be able to get cos(α+β)=0 {where α and β are the angles made by the final velocity vectors with the initial direction of motion).
Problem 64 is an extension of 63

P.S. assume the X axis to be along the initial velocity.
 
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  • #3
Sunil Simha said:
For problem 63, apply the equations for conservation of kinetic energy and conservation of momentum along the x and y axes. By a few steps of mathematical juggling you should be able to get cos(α+β)=0 {where α and β are the angles made by the final velocity vectors with the initial direction of motion).
Problem 64 is an extension of 63

P.S. assume the X axis to be along the initial velocity.

Alright. Ok, I did a mistake while reading the question ! It was not a "Head On" collision, though elastic.

Applying conservation of linear momentum :

v1 + v2 = u1

Note that mass cancels and symbols denote the general meaning as I stated in the previous post. Writing in magnitude form :

v12+v22+2v1v2cos(θ) = u12 ...(i)

Applying conservation of kinetic energy :

Note that factor m/2 cancels and,

v12+v22=u12 ...(ii)

Subtracting (ii) from (i) , we get :

v1v2cosθ=0. This implies θ=90o

θ is angle between two final velocity vectors.

I could have also done this by component method.

Thanks a bunch Sunil !

Now to next question :

Can I get more hints ?

Also, are you preparing for IIT ? Did you recognize the book from which I asked this question ? :)
 
  • #4
Yes I'm preparing for the JEE too. Good to see a fellow student. No, I did not recognize the book (I'm guessing Irodov). As for the next question, now that you are armed with the result of the Q63, I guess you should be able to solve it.
 
  • #5
Sunil Simha said:
Yes I'm preparing for the JEE too. Good to see a fellow student. No, I did not recognize the book (I'm guessing Irodov). As for the next question, now that you are armed with the result of the Q63, I guess you should be able to solve it.

Yep solved it ! Thanks again. And it was from H.C. Verma. BTW, I have just passed 11th.

And regarding your PM:

My internet was unable to load the image of that thread, which "Beast" posted. When I try to open it in a separate tab, it gives a server error.
 

FAQ: Two questions regarding linear momentum and conservation

What is linear momentum?

Linear momentum is a physical quantity that describes the motion of an object. It is defined as the product of an object's mass and its velocity. It is a vector quantity, meaning it has both magnitude and direction.

How is linear momentum calculated?

Linear momentum (p) is calculated by multiplying an object's mass (m) by its velocity (v): p = m x v. The SI unit for linear momentum is kg*m/s.

What is the principle of conservation of linear momentum?

The principle of conservation of linear momentum states that the total linear momentum of a closed system (a system with no external forces acting on it) remains constant. This means that in a closed system, the initial momentum of all objects before a collision or interaction is equal to the final momentum of all objects after the collision or interaction.

How is conservation of linear momentum applied in real-life situations?

Conservation of linear momentum is applied in various real-life situations, such as collisions between objects, explosion of projectiles, and rocket propulsion. It is also used in engineering and design to ensure the safety and efficiency of structures and machinery.

What is the difference between elastic and inelastic collisions in terms of linear momentum?

In an elastic collision, the total linear momentum of the system is conserved, meaning the sum of the initial momentums of the objects is equal to the sum of the final momentums. In an inelastic collision, some of the kinetic energy is lost, resulting in a decrease in the total linear momentum of the system. However, the principle of conservation of linear momentum still holds true for both types of collisions.

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