- #1
Yroyathon
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hi again folks. this week's set of problems is getting my goat. here's another I can't seem to figure out.
In a neutron two-slit diffraction experiment, the slits are 65 µm apart. If the third diffraction maximum is detected at an angle of 2 multiplied by 10-7 rad, what is the kinetic energy of the neutrons?
E=h*f=(h*c)/lambda
d * sin theta_n = n * lambda
I set d = 65 * 10^(-6), and n=3. theta_n = 2*10^(-7). I used this to solve for lambda. Given the energy equation, I computed (h*c)/lambda to get 4.59 * 10^(-14) eV, but this is wrong. I thought I had a clear application of this equation here, but there has to be something I'm not quite getting that's different, that I'm not taking into account here.
can anyone see what I've missed?
I'd appreciate any ideas you might have.
,Yroyathon
Homework Statement
In a neutron two-slit diffraction experiment, the slits are 65 µm apart. If the third diffraction maximum is detected at an angle of 2 multiplied by 10-7 rad, what is the kinetic energy of the neutrons?
Homework Equations
E=h*f=(h*c)/lambda
d * sin theta_n = n * lambda
The Attempt at a Solution
I set d = 65 * 10^(-6), and n=3. theta_n = 2*10^(-7). I used this to solve for lambda. Given the energy equation, I computed (h*c)/lambda to get 4.59 * 10^(-14) eV, but this is wrong. I thought I had a clear application of this equation here, but there has to be something I'm not quite getting that's different, that I'm not taking into account here.
can anyone see what I've missed?
I'd appreciate any ideas you might have.
,Yroyathon