- #1
yasar1967
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I'm trying to be 100% sure if I get this experiment right and it's complications as it obviously is a base to quantum physics.
During the experiment and when electrons are fired one by one, immediately leaving the gun, an electron has an infinite number of choices/paths until it hits the screen.
The electron gun makes all possible choices/paths to collect on one place which is the very straight path up to the screen as the momentum it gives to electrons requires so. Otherwise the electrons would spread out to universe equally, statistically.
Electron is everywhere, not just on the screen where we have more likely to find than in any other places after it leaves the gun.
Electron gun's mere function is to concentrate them on the straight path, again statistically. If we do not use ANY slits at all what we see is the wave collapse function of infinite possibilities but mostly and statistically on the very straight path. What seems as a chunk of electrons displayed on the screen is actually collapsed wave functions of infinite electrons, no patterns. As a matter of fact it's not "no-patterns", it's the collections of "n" wave patterns.
When we use two slits, on the other hand, we eliminate all the other possible wave functions but allow these two to reach to the screen.
That's why it doesn't matter if we fire them one by one or in bulk, their collective wave function is pre-determined, what we see is what we "choose" to see. If we choose to see only TWO of the "n" wave collapses, we use two slits, if three then so on.
It's not that electron leaves the gun as a "single" entity but when it comes near to the slit it splits into two. It leaves the gun as "n" entity all following a different path and the two possible routes we choose to observe and these two paths' overlap we see on the screen.
Am I right or am I right ? :)
During the experiment and when electrons are fired one by one, immediately leaving the gun, an electron has an infinite number of choices/paths until it hits the screen.
The electron gun makes all possible choices/paths to collect on one place which is the very straight path up to the screen as the momentum it gives to electrons requires so. Otherwise the electrons would spread out to universe equally, statistically.
Electron is everywhere, not just on the screen where we have more likely to find than in any other places after it leaves the gun.
Electron gun's mere function is to concentrate them on the straight path, again statistically. If we do not use ANY slits at all what we see is the wave collapse function of infinite possibilities but mostly and statistically on the very straight path. What seems as a chunk of electrons displayed on the screen is actually collapsed wave functions of infinite electrons, no patterns. As a matter of fact it's not "no-patterns", it's the collections of "n" wave patterns.
When we use two slits, on the other hand, we eliminate all the other possible wave functions but allow these two to reach to the screen.
That's why it doesn't matter if we fire them one by one or in bulk, their collective wave function is pre-determined, what we see is what we "choose" to see. If we choose to see only TWO of the "n" wave collapses, we use two slits, if three then so on.
It's not that electron leaves the gun as a "single" entity but when it comes near to the slit it splits into two. It leaves the gun as "n" entity all following a different path and the two possible routes we choose to observe and these two paths' overlap we see on the screen.
Am I right or am I right ? :)