- #1
matt23721
- 5
- 0
Hey guys, I am new here, i was wondering if you could help me solve the following problems
ok...A stone is thrown vertically upward at a speed of 48.70 m/s at time t=0. A second stone is thrown upward with the same speed 4.390 seconds later. At what time are the two stones at the same height?
now i know the height where they meet is: 7.159s, but i can't solve the other part:
At what height do the two stones pass each other?
What is the downward speed of the first stone as they pass each other?
any help would be appreciated
thanks!
ok...A stone is thrown vertically upward at a speed of 48.70 m/s at time t=0. A second stone is thrown upward with the same speed 4.390 seconds later. At what time are the two stones at the same height?
now i know the height where they meet is: 7.159s, but i can't solve the other part:
At what height do the two stones pass each other?
What is the downward speed of the first stone as they pass each other?
any help would be appreciated
thanks!