Two vector operations and simple expressions

In summary, vector operations involve manipulating mathematical quantities that have both magnitude and direction. Two common operations are vector addition, which involves combining two vectors to create a new vector, and scalar multiplication, which involves multiplying a vector by a scalar quantity to change its magnitude. Simple expressions involving vectors can also be simplified using mathematical rules, such as the distributive property. These operations are essential in various fields, including physics, engineering, and mathematics.
  • #1
JiWang
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Thread moved from the technical forums to the schoolwork forums
TL;DR Summary: My problems comes to a vector expression which needs to be simplified

I got an expression
piijksk,lul,j
Here s and u are two vectors. What will be the vector expression of this vector p with curl s, curl u, and other operations?
 
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  • #3
BvU said:
Hello @JiWang ,
:welcome: ##\qquad## !​

Please post the complete problem statement; see https://www.physicsforums.com/threads/homework-help-guidelines-for-students-and-helpers.686781/

Also, I don't see any vectors on the righthand side in piijksklulj

##\ ##
I thought that too, but on closer inspection there are commas between the subscripts in the OP. Much clearer in LaTeX: ##s_{k,l}=\partial_ls_k## and similarly ##u##. @JiWang, you should also read the LaTeX Guide.
 
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  • #5
JiWang said:
TL;DR Summary: My problems comes to a vector expression which needs to be simplified

I got an expression
piijksk,lul,j
Here s and u are two vectors. What will be the vector expression of this vector p with curl s, curl u, and other operations?

Use [tex]
(\partial_j u_l) (\partial_l s_k) = \partial_j ( u_l \partial_l s_k) - u_l \partial_j \partial_l s_k.[/tex] Then you can write your expression as [tex]
\mathbf{p} = \nabla \times (\mathbf{u} \cdot \nabla \mathbf{s}) - \mathbf{u} \cdot \nabla ( \nabla \times \mathbf{s}).[/tex]
 
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  • #6
Can you expand them to single operations? Thanks.
 
  • #7
JiWang said:
Can you expand them to single operations? Thanks.
See the homework guidelines. @pasmith has already done more than enough of your homework!
 

FAQ: Two vector operations and simple expressions

What are the basic vector operations?

The basic vector operations include vector addition, vector subtraction, scalar multiplication, and dot product. Vector addition involves adding corresponding components of two vectors. Vector subtraction involves subtracting corresponding components. Scalar multiplication involves multiplying each component of a vector by a scalar. The dot product is a scalar value obtained by multiplying corresponding components of two vectors and summing the results.

How do you add two vectors?

To add two vectors, you add their corresponding components. For example, if you have vectors A = (a1, a2) and B = (b1, b2), their sum A + B = (a1 + b1, a2 + b2). This operation can be extended to vectors of any dimension by adding each corresponding component.

What is the dot product of two vectors and how is it calculated?

The dot product of two vectors is a scalar value that is calculated by multiplying corresponding components of the vectors and then summing those products. For two vectors A = (a1, a2, ..., an) and B = (b1, b2, ..., bn), the dot product is given by A · B = a1*b1 + a2*b2 + ... + an*bn. The dot product is often used to determine the angle between two vectors or to check for orthogonality.

What is scalar multiplication of a vector?

Scalar multiplication of a vector involves multiplying each component of the vector by a scalar (a real number). For example, if you have a vector A = (a1, a2) and a scalar k, the result of scalar multiplication kA = (k*a1, k*a2). This operation scales the vector by the scalar value, affecting its magnitude but not its direction.

How do you subtract one vector from another?

To subtract one vector from another, you subtract their corresponding components. For example, if you have vectors A = (a1, a2) and B = (b1, b2), their difference A - B = (a1 - b1, a2 - b2). This operation can be extended to vectors of any dimension by subtracting each corresponding component.

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