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magnetpedro
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I'm using a U-Shaped Ferrite Core with coils in both legs of the U.
I've calculated it's inductance using an analogy between electric/magnetic circuits.
L = N2/Rtotal
where:
N = number of turns of coil in both legs of the U;
Rtotal is the total reluctance of my circuit = R1 + R2
R1 = l1/μ0*μr,core*A
R2 = l2/μ0*μr,air*A
R1 is the reluctance of the circuit within the Ferrite core, where l1 is the mean length of the circuit (=0,189m), μr,core is the relative permeability of the core (≈1000) and A is the cross-sectional area (=7e-4 m2).
R2 is the reluctance of the air gap between both legs of the Ferrite core, where l2 is the mean length of the magnetic circuit (=0,093m), μr,air. =1, and the A is the same as in R1.
I get a value of L =1,51 mH for a total of 400 turns of coil (N=400).
When I plug it to a LCR meter , with a current of 19,91 mA the inductance L equals 14,21 mH.
Can someone tell me how I can relate both inductances?
Thanks in advance[/SUB]
I've calculated it's inductance using an analogy between electric/magnetic circuits.
L = N2/Rtotal
where:
N = number of turns of coil in both legs of the U;
Rtotal is the total reluctance of my circuit = R1 + R2
R1 = l1/μ0*μr,core*A
R2 = l2/μ0*μr,air*A
R1 is the reluctance of the circuit within the Ferrite core, where l1 is the mean length of the circuit (=0,189m), μr,core is the relative permeability of the core (≈1000) and A is the cross-sectional area (=7e-4 m2).
R2 is the reluctance of the air gap between both legs of the Ferrite core, where l2 is the mean length of the magnetic circuit (=0,093m), μr,air. =1, and the A is the same as in R1.
I get a value of L =1,51 mH for a total of 400 turns of coil (N=400).
When I plug it to a LCR meter , with a current of 19,91 mA the inductance L equals 14,21 mH.
Can someone tell me how I can relate both inductances?
Thanks in advance[/SUB]
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