Uncertainty momentum position velocity

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The discussion revolves around calculating the minimum uncertainty in the position of an electron given its velocity and uncertainty in velocity. The relevant equation used is delta(x) * delta(P) >= hbar/2, where delta(P) is derived from the uncertainty in velocity multiplied by the mass of the electron. The participant confirms that they can compute delta(x) without needing the specific position or velocity values. The response emphasizes careful notation in calculations to avoid confusion. The conclusion is that the necessary information for the calculation is sufficient without specific values for position and velocity.
jackxxny
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Homework Statement



I have a dilemma. My problem states that an electron that is in position 2.34 nm along the x axis, travels along the x-axis with a certain speed (A) and a with the uncertainty in the velocity (B). I am asked to calculate the minimum uncertainty in the position.

Homework Equations



I know

delta(x)*delta(P)>= hbar/2
delta(P)= delta(v)*(mass electron)

for delta(v) I'm going to use the B

The Attempt at a Solution



I have done this

delta (x) = (hbar)/2*(delta(v))*(mass electron)

my question is, i don't need the position and the velocity then
 
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jackxxny said:
I have done this

delta (x) = (hbar)/2*(delta(v))*(mass electron)
Careful with parentheses--it's hard to tell if you are multiplying or dividing by delta(P).

my question is, i don't need the position and the velocity then
That's right--you don't need that information.
 
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