Uncertainty of a single photon in light scattering question

In summary, the photon's wavefunction and probability expands out like a sphere. When a photon is detected, the wavefunction collapses and the photon momentum is in the direction of the detector. If the photon is not detected, but is assumed to have been emitted, the wavefunction is still affected by the detector.
  • #1
invisigo
10
0
I have a mental picture of photon scattering that goes like this:

An atom spontaneously emits a single photon (or particle). Since the photon hasn't been observed, its wavefunction and probability expands out like a sphere. If I take my photodetector and place it at some point on this expanding sphere, I will detect this photon with probability 1/(4*Pi*radius). If I detect the photon, this collapses the wavefunction and I say the photon momentum was in the direction of my photodetector. If I don't detect the photon, but I know it was emitted, the photon is still traveling in a outward sphere. Or is the wavefunction now affected by my photodetector?

Can anyone comment on this picture?
 
Physics news on Phys.org
  • #2
I think it is very dangerous to assume that "photon is propagating in the form of a spherical wave, which collapses when it reaches the photodetector". If you take this statement as the actual physical mechanism of what happens, then there are lots of unpleasant questions that you would be forced to answer. For example, what is the physical interaction responsible for the collapse? Will the photon's "wave" collapse if instead of the photodetector you put there a piece of wood?

I think it is better to use the following explanation: We cannot say for sure what happens with the photon while it is not observed. Whatever statement we make about the non-observed photon, this statement is empty, because it cannot be verified experimentally (simply due to the condition that the photon is not observed). Any statement that cannot be directly verified by experiment should not belong to physics. The best thing we can do is to suggest a mathematical model (photon's state described by a complex spherical wave function or by a vector in the Hilbert space). This abstract model (which does not attempt to provide a physical mechanism of the photon's propagation) is sufficient to predict the outcomes of measurements (the probability that the detector will click) with good accuracy. This agreement with experiment is all we can (and should) ask from a successful physical theory, such as quantum mechanics.

If you accept quantum mechanics (wave functions etc.) as an abstract mathematical model rather than a physical mechanism of non-observed events, then all paradoxes and inconsistencies will go away.
 
  • #3
Hi invisigo,

Good, Shaking Fundamentals of QM, let's say, instead of a photo detector you have an electron the way to calculate Wave function is to apply Schrodinger equation indicating the presence of the electron(you will be adding Potential Energy due to the electron etc.),once you know the Hamiltonian you can get the dynamics of the wavefunction.But if you have a classical object like the photo detector I really don't know how to solve the issue(the collapse concept is very difficult for Humans to understand, this is my opinion but I don't know the current situation).
 

FAQ: Uncertainty of a single photon in light scattering question

What is the uncertainty of a single photon in light scattering?

The uncertainty of a single photon in light scattering refers to the degree of unpredictability or imprecision in the measurement of the position or momentum of a single photon during the process of light scattering. This uncertainty is a fundamental aspect of quantum mechanics and is described by Heisenberg's uncertainty principle.

How is the uncertainty of a single photon in light scattering calculated?

The uncertainty of a single photon in light scattering is calculated using Heisenberg's uncertainty principle, which states that the product of the uncertainties in the position and momentum of a particle must be greater than or equal to a certain value, known as Planck's constant divided by 4π. This calculation takes into account the inherent randomness and unpredictability of quantum particles.

What factors can affect the uncertainty of a single photon in light scattering?

The uncertainty of a single photon in light scattering can be affected by various factors, such as the type of material or medium through which the light is scattering, the angle of incidence and scattering, and the energy of the photon. Additionally, the uncertainty can also be influenced by the measurement apparatus and techniques used to measure the position and momentum of the photon.

Can the uncertainty of a single photon in light scattering be reduced?

No, according to Heisenberg's uncertainty principle, the uncertainty of a single photon in light scattering cannot be reduced beyond a certain limit. This is because the act of measuring the position or momentum of a particle inevitably disturbs its state, making it impossible to know both quantities simultaneously with absolute precision.

How does the uncertainty of a single photon in light scattering impact scientific research and technology?

The uncertainty of a single photon in light scattering plays a crucial role in many areas of scientific research and technology, particularly in the fields of quantum mechanics, optics, and photonics. Understanding and accounting for this uncertainty is essential for developing accurate models, simulations, and devices that rely on the behavior of photons and their interactions with matter.

Similar threads

Replies
21
Views
2K
Replies
3
Views
1K
Replies
29
Views
2K
Replies
36
Views
4K
Replies
7
Views
1K
Replies
25
Views
11K
Back
Top