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thewestbrew
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Homework Statement
A 42.5kg person is going down a hill sloped at 42.0 degrees. The coefficient of kinetic friction between the snow and skis is 0.180. How fast is the skier going 4.56 seconds after starting from rest?
Homework Equations
Is ffkmax equal to net force?
The Attempt at a Solution
coefficient of kinetic friction:.180 t=4.56 mass=42.5kh Angle=42 degrees Vo=0
I created a free body diagram.
I used (mg)(cos 42) to get total force going opposite of FN. I made that force equal to FN and plugged the number into the equation ffkmax=coefficient(.180)*FN(315.83).
Got 76.5N=ffkmax. Now I am not sure if i use fnet=ma or a motion equation.